Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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Answer:
k = 4
Step-by-step explanation:
Given that a varies directly as b then the equation relating them is
a = kb ← k is the constant of variation
To find k use the condition a = 8 when b = 2
k = 
= 
= 4
Answer:
D
Step-by-step explanation:
because we know that angle EOD is less the 90 so that means that it is complementary. For AOB it is the same but we can check by adding 35 plus x plus 90 =180 degrees so 35+90=125 x=180-125=55 so x=55 and 55 is less then 90 so it is a complementary angle.
F(x)=(3x-2)^0.5
C.x is greater than or equal to two thirds
B how many ways can they register for the same section
