Answer:
<h2>
31.7 cm^2</h2>
Solution,
In ∆ ABC
< A + <B + < C = 180°
or, 72 + 59 + <C = 180°
or, 131 + <C = 180°
or, <C = 180 - 131
< C = 49
Area of ∆ABC = 1/2 ab sin C
= 1/2 * 12 * 7 * sin 49
= 42 * sin 49
= 31.7 ( approximately)
Hope this helps...
Good luck on your assignment...
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48 : (17 - 15)³ - 5 = 48 : 2³ - 5 =
= 48 : 8 - 5 = 6 - 5 = <u>1</u>
<h3><u>Answer</u><u>:</u><u>-</u></h3>
x=17
<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

<h3 />
This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.
<h3><u>Solution</u><u>:</u><u>-</u></h3>
Given angles
According to sum theory



- Together like polynomials and constants






