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Semmy [17]
3 years ago
13

If 4 bushels of rye weigh 76 lb, how much do 8.5 bushels of rye weigh?

Mathematics
2 answers:
mina [271]3 years ago
5 0
76/4=19 lb is weighht of 1 bushel of rye
19*8.5=161.5 lb

8.5 bushels of rye weigh 161.5 lb
Verizon [17]3 years ago
3 0
I believe that would be 161.5 lbs. This is because using division(76 divided by 4) we find that each bushel weighs 19 lbs.  So then we would multiply (19 x 8= 152) and finally add the half a bushel(152+9.5=161.5).
Hope it helps!
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5 0
3 years ago
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3 0
3 years ago
three families are traveling the same route across country. the first family stops every 240 kilometers. the second family stops
kogti [31]

Answer:

<u>The three families will stop at the same place at 1,200 kilometers.</u>

Step-by-step explanation:

1. Let's check all the information given to answer the question:

Family A or 1 stops every 240 kilometers

Family B or 2 stops every 200 kilometers

Family C or 3 stops every 300 kilometers

2. After how many kilometers will they stop at the same place?​

Family A or 1 will stop at 240, 480, 720, 960 and 1,200 kilometers.

Family B or 2 will stop at 200, 400, 600, 800. 1,000 and 1,200 kilometers.

Family C or 3 will stop at 300, 600, 900. and 1,200 kilometers.

<u>As we can check the first common stop will be at 1,200 kilometers.</u>

7 0
3 years ago
Which number produces an irrational number when multiplied by 1/3
MArishka [77]

We can simply observe that.

  1. 0.777... is rational, because it is a number with infinite but repeating decimal part.
  2. 1/3 is rational, because it's the division between two integers
  3. -\sqrt{16}=-4, so this is rational as well.

Since the product of two rational numbers is always rational, we have that

0.\bar{7}\cdot \dfrac{1}{3},\quad \dfrac{1}{3}\cdot \dfrac{1}{3},\quad -4\cdot \dfrac{1}{3}

are all rationals, since they are the product of two rationals.

On the other hand, we have

\sqrt{27}=\sqrt{9\cdot 3}=3\sqrt{3}

and thus

3\sqrt{3}\cdot \dfrac{1}{3}=\sqrt{3}

which is irrational.

3 0
3 years ago
How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50
Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of \frac{5}{6} kilogram of candy is $7.5

- We need to find the cost of 4\frac{5}{7} kilogram

We  can use the ratio to find the answer

======= Dollar   :    Kilogram

======= 7.5        :    \frac{5}{6}

=======  c           :    4\frac{5}{7}  

By using cross multiplication

∴ c × \frac{5}{6} = 7.5 × 4\frac{5}{7}

∵ 4\frac{5}{7} = \frac{4*7+5}{7}

∴ 4\frac{5}{7} = \frac{33}{7}

∴ c × \frac{5}{6} = 7.5 × \frac{33}{7}

∴ c × \frac{5}{6} = \frac{495}{14}

Divide both sides by \frac{5}{6}

∴ c = \frac{495}{14} ÷ \frac{5}{6}

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = \frac{495}{14} × \frac{6}{5}

∴ c = \frac{297}{7} = 42.43 dollars

∵ c represents the cost of 4\frac{5}{7} kg

∴ It costs $42.43

7 0
4 years ago
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