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irakobra [83]
3 years ago
7

What is the median of 5, 7, 2, 4, 3 (remember to place the numbers in order first.)

Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

4

Step-by-step explanation:

The numbers in order would be

2, 3, 4, 5, 7

The number in the middle is always the median

Therefore, 4 is the median

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(X^3+1)dividend (x-1)
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x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

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3 years ago
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Step-by-step explanation:

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3 years ago
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3 years ago
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Pls help me answer this question
docker41 [41]

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3 years ago
What is the circumference of a circle with weight of 3 1/8 inches?
MrRissso [65]
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