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Leni [432]
3 years ago
9

What is the numeral for forty-two?

Mathematics
2 answers:
Bezzdna [24]3 years ago
7 0

Answer:

Step-by-step explanation:

If you mean what I think the answer is 42

if you mean roman numeral its XLII

GREYUIT [131]3 years ago
3 0

Answer:

it is XLII

Step-by-step explanation:

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Help me answer this question about congruent triangles. 50 points available.
Anuta_ua [19.1K]

Answer:

B

Step-by-step explanation:

No these triangles are not congruent.

<u>Left triangle</u>

Shortest side = 6 cm

Longest side = 13 cm

3rd side = unknown but < 13

<u>Right triangle</u>

Shortest side = 6 cm

Longest side = unknown but > 13

3rd side = 13 cm

Although the shortest side of both triangles is 6 cm, the longest side of the left triangle is 13 cm, whereas the longest side of the right triangle is unknown but will be more than 13 cm.

We do not know if any of the angles are congruent.  If they were congruent, we would expect to see this marked by the same angle line(s) on each triangle.

3 0
2 years ago
2 divided by one over 3 the awnser is a fraction
slamgirl [31]

Answer:

That would equal \frac{2}{3} or approximately 0.67. If this helps, please rank Brainliest. Thanks!

4 0
3 years ago
Read 2 more answers
Explain why segments connecting any pair of corresponding vertices of congruent pentagons are congruent. make a sketch to suppor
Veronika [31]

Answer:

Congruence between pentagons

Step-by-step explanation:

The relationship occurs because having two congruent Pentagons and generating a segment within them (or outside), congruence is extrapolated to the triangles generated within them. Thus, if there is congruence among the pentagons, it will exist between the formed triangles. In other words since the two pentagons are congruent, the corresponding angle pair is congruent. also the two corresponding side pairs are also congruent.

In the attached image for example, the ABCDE and KLMNO pentagons are congruent, so all of their internal division lines are also congruent (AC and KM)

8 0
2 years ago
Write down a differential equation of the form dy/dt = ay + b whose solutions have the required behavior as t → ∞. all other sol
nordsb [41]

The ODE has an equilibrium point at

\dfrac{\mathrm dy}{\mathrm dt}=ay+b=0\implies y=-\dfrac ba

We want y=2 to be an unstable equilibrium solution - in other words, we want all solutions with initial condition y(t_0)=c for c near 2 to diverge from y=2 - so -dfrac ba=2.

Divergence from y=2 would require that for y>2, any solution is increasing, and for y, and solution is decreasing. In order for that to happen, we need

\dfrac{\mathrm dy}{\mathrm dt}=ay+b>0\implies y>-\dfrac ba

if y>2, and

\dfrac{\mathrm dy}{\mathrm dt}=ay+b

if y.

Now we just pick a,b to satisfy these conditions. An easy choice is a=1, which forces b=-2, so that one possible ODE would be

\dfrac{\mathrm dy}{\mathrm dt}=y-2

I've attached a plot of the slope field to demonstrate the behavior of the solutions.

6 0
3 years ago
Solve for x <br> 3(x - 2) = 6x - 12
svetoff [14.1K]

Answer:x=2

Step-by-step explanation:

3(x-2)=6x-12

3x-6=6x-12

Collect like terms

6x-3x=12-6

3x=6

Divide both sides by 3

3x/3=6/3

x=2

6 0
3 years ago
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