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KonstantinChe [14]
3 years ago
8

6 times a number subtracted from 49 is 5

Mathematics
2 answers:
vitfil [10]3 years ago
8 0
The answer is 9 because 6 times 9 equals 54 and then subtracted from 49 equals 5

<u><em>*Hope I Helped*</em></u>
Dmitry [639]3 years ago
4 0
49-6n=5 subtract 49 from both sides -6n= -44 divide by -6 n= 22/3 hope this helps
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Which expression has a sum of one and two twenty ones?
ivanzaharov [21]
Its A

3/7 + 2/3 = 23/21

and 23/21 as a mixed number is:

1 and 2/21
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2 years ago
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A zookeeper is monitoring the population of gazelles. The herd needs three times more males than females to thrive, and the zoo
avanturin [10]

Answer:

0 < x ≤ 12 and 0 < y ≤ 36

Step-by-step explanation:

Here,  x represents the number of female gazelles and y represents  the number of male gazelles.

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12 ≥ x

Also, number of animals can not be negative,

And, it must be greater than 0.

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Hence, the constraints to represent a thriving population of gazelles at the zoo are,

0 < x ≤ 12,

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7 0
2 years ago
Read 2 more answers
Johnathan has been driving at a constant speed for 4 hours, during which time he traveled 240 miles Johnathan world like to know
valentinak56 [21]
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8 0
3 years ago
Solve the problem:
stepan [7]

volume of the box is 675 cubic inches

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It is a square sheet so length and width are same

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After turning up the sides the height of the box becomes 3 inches

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5 0
3 years ago
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
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