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3 years ago

You need to lay communications cable around the perimeter of three offices, each 8' by 10'. How much cable do you need?

Mathematics

1 answer:

ryzh [129]3 years ago

6 0

Answer:

108 units

Step-by-step explanation:

We are given that

Length of each office,l=10 units

Breadth of each office=b=8 units

Total number of office=3

We know that

Perimeter of rectangle= $2(l+b)$

Using the formula

Length of cable for 1 office= $2(10+8)=36units$

Length of cable required for 3 offices= $36\times 3=108$ units

Hence, the required length of cable=108 units

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Solving linear systems of substitution

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2x + 2(-2/3x + 6) = 8.
Then you would distribute the 2 into the parenthesis and simplify to solve for x.
After you solve for x, plug x into one of the original equations to find y.

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Answer:

Step-by-step explanation:

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3 years ago

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2 years ago

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3 years ago

I do draws a blueprint of a house using the scale 1 in equals 6 ft in the kitchen has a length of 24 ft what is the length of th

ikadub [295]

Answer:

Length of kitchen on blueprint = 4 in.

Step-by-step explanation:

Scale used to draw a blueprint of a house :

6 feet = 1 in.

Therefore, 1 feet = $\frac{1}{6}$ in.

If the length of kitchen = 24 feet

Then the length of kitchen on the blueprint will be

= $\frac{1}{6}\times 24$

= 4 in.

Therefore, length of kitchen on blueprint is 4 in.

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3 years ago