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Andreyy89
3 years ago
5

You need to lay communications cable around the perimeter of three offices, each 8' by 10'. How much cable do you need?

Mathematics
1 answer:
ryzh [129]3 years ago
6 0

Answer:

108 units

Step-by-step explanation:

We are given that

Length of each  office,l=10 units

Breadth of each office=b=8 units

Total number of office=3

We know that

Perimeter of rectangle=2(l+b)

Using the formula

Length of cable for 1 office=2(10+8)=36units

Length of cable required for 3 offices=36\times 3=108units

Hence, the required length of cable=108 units

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Answer:

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Step-by-step explanation:

did the test

0.3(4x-8)-0.5(-2.4x+4)

=1.2x-2.4-0.5(-2.4x+4)

=1.2x-2.4+1.2x-2

=2.4x-4.4

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3 years ago
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I WILL MARK YOU BRAINLYEST if you answer all of my problems !!!!!!!!!!!
sweet-ann [11.9K]
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Hope this helped!
3 0
3 years ago
Add the fractions and simplify the answer 1/2 +2 /3
IrinaVladis [17]
What we are going to do is add \frac{1}{2} by \frac{2}{3}. The first thing we do is make common denominators for \frac{1}{2} and \frac{2}{3}:\frac{1*3}{2*3}= \frac{3}{6} \ and \  \frac{2*2}{3*2}= \frac{4}{6}. Now we add \frac{3}{6} by \frac{4}{6}: \frac{3}{6}+ \frac{4}{6}= \frac{7}{6}. Now we make \frac{7}{6} a mixed number:\frac{7}{6}=1 \frac{1}{6}. Therefore, your answer is \boxed{\boxed{1 \frac{1}{6}}}. Hoped I helped. :)
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