Question

Describe how the graph of y = -1/4 arccos(x – 3) + 1 is a transformation of y = arccos(x). O Vertical Stretch of , a reflection about the x-axis, a vertical translation of 3 up, and a horizontal translation of 1 right Horizontal Stretch of 4, a reflection about the y-axis, a vertical translation of 1 down, and a horizontal translation of 3 left Horizontal Stretch of 4, a reflection about the y-axis, a vertical translation of 3 down, and a horizontal translation of 1 left. Vertical Stretch of, a reflection about the x-axis, a vertical translation of 1 up, and a horizontal translation of 3 right.​

Answer 1

Using translation concepts, it is found that the option that describes the graph of $y = -\frac{1}{4}\arccos{(x - 3)} + 1$ compared to the graph of $y = \arccos{x}$ is:

• Vertical Stretch of $\frac{1}{4}$, a reflection about the x-axis, a vertical translation of 1 up, and a horizontal translation of 3 right.​

The parent function is:

$y = \arccos{x}$

What is a translation?

• A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem:

• First, the function was multiplied by $-\frac{1}[4}$, hence it was vertically strech by a factor of $\frac{1}{4}$, which is the same as a compression, and reflected over the x-axis.

• $x \rightarrow x - 3$, hence, it was shifted horizontally 3 units to the right.

• 1 was added, hence it was shifted vertically 1 unit up.

You can learn more about translation concepts at brainly.com/question/26149145