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ValentinkaMS [17]
2 years ago
11

Given the equation y = -3x +1/2 , what is the y-intercept?

Mathematics
1 answer:
pychu [463]2 years ago
3 0

y  intercept = 1/2

<u>Step-by-step explanation:</u>

Step 1:

Formula y=mx+b in Slope Intercept form( whereas m= slope of the given equation, b= y intercept)

Step 2:

Comparing the given equation y = -3x + 1/2

we get  m=-3(Slope) and y-intercept b=1/2

You might be interested in
Find the area of a circle that has a diameter of 11 inches. Approximate r as 3.14. Round your answer to the nearest
mylen [45]

Answer:

94.985in^2

Step-by-step explanation:

Given data

Diameter= 11inches

Radius = 5.5 in i.e 11/2= 5.5inches

The  Area of a circle is given as

Area= πr^2

Substitute

Area= 3.14*5.5^2

Area= 3.14*30.25

Area= 94.985 in^2

Hence the area is 94.985in^2

5 0
2 years ago
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
Which is equivalent to 23·2-5?<br> A) 2-15 <br> B) 2-8 <br> Eliminate<br> C) 2-2 <br> D) 22
bulgar [2K]
2^3 * 2^-5 = 2^(3 + (-5) = 2^(3 - 5) = 2^-2
4 0
3 years ago
Please help thank you
sergiy2304 [10]
8-3(2)
8-5
=3
the answer should be 3 after plugging in the variables.

3 0
3 years ago
(01.02)
Bas_tet [7]

Step-by-step explanation:

it is option c. you interchange the value with y and take inverse.

8 0
2 years ago
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