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3 years ago

11

A bag contains 2 blue, 4 green, and 3 white chips. What is the probability of drawing a blue chip, replacing it, then drawing a

green chip? Question 1 options: 1/12 2/3 8/81 7/9

1 answer:

Brrunno [24]3 years ago

4 0

2 blue, 4 green, 3 white....total of 9 chips

P(blue) = 2/9
replacing
P(green) = 4/9

P(both events happening) = 2/9 * 4/9 = 8/81 <==

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3 years ago

7. If U= {2, 4, 6, 8, 10, 12, 14, 16} and<br> A = {6, 10, 14}, what is A'?

Tresset [83]

The compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

We are given the universal set as:

U = {2, 4, 6, 8, 10, 12, 14, 16}

We are also given that set A is:

A = {6, 10, 14}

We need to find A'

For this, we will subtract set A from the universal set, U.

So, we get that:

A' = U - A

A' = {2, 4, 6, 8, 10, 12, 14, 16} - {6, 10, 14}

Solving the expression, we get that:

A' = {2, 4, 8, 12, 16}

Therefore, we get that, the compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

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brainly.com/question/2166579

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1 year ago

The playing life of a Sunshine radio is normally distributed with mean LaTeX: \muμ = 600 hours and standard deviation LaTeX: \si

Hitman42 [59]

Answer:

The probability that a radio selected at random will last from 600 to 700 hours is 0.3413

Step-by-step explanation:

The playing life of a Sunshine radio is normally distributed

Mean = $\mu = 600 hours$

Standard deviation = $\sigma = 100 hours$

We are supposed to find the probability that a radio selected at random will last from 600 to 700 hours i.e.P(600<x<700)

Formula: $Z= \frac{x-\mu}{\sigma}$

At x = 600

$Z= \frac{600-600}{100}$

Z=0

$P(X$

At x = 700

$Z= \frac{700-600}{100}$

Z=1

$P(X$

$P(600$

Hence the probability that a radio selected at random will last from 600 to 700 hours is 0.3413

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3 years ago