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3 years ago

What is the 5th term in the following sequence: 2, 5, 11, 23... Helpppp

1 answer:

4 0

Answer:The first few Thabit numbers are: 2, 5, 11, 23, 47, 95, 191, 383, 767, 1535, 3071, 6143, 12287, 24575, 49151, 98303, 196607, 393215, 786431, 1572863, ...

...

Thabit number.

Named after Thābit ibn Qurra

First terms 2, 5, 11, 23, 47, 191, 383, 6143, 786431

Largest known term 3×211,895,718 − 1

OEIS index A007505

Step-by-step explanation:

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As shown in the diagram below, AABC - A DEF, AB=14, BC=4, DE=7, and EF = X

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EF=4

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3 years ago

Show your work:<br><br> Express 160 pounds (lbs) in kilograms (kg). Round to the nearest hundredths.

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Answer:

160 lbs = 72.57kg

Step-by-step explanation:

This can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

Each lb has 0.45kg. How many kg are there in 160lbs. So:

1lb - 0.45kg

160 lbs - xkg

$x = 0.45*160$

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3 years ago

Find the indicated function values for the function f(x) = 3x² + 2x - 6.

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The function values for the function f(x) = 3x² + 2x - 6, for the values are:

a. f(0) = -6

b. f(2) = 10

c. f(-4) = 34

d. f(b) = 3b² + 2b - 6

e. f(4a) = 48a² + 8a - 6

<h3>How are function values calculated?</h3>

To calculate function value f(k) for a function f(x), we substitute variable x = k, in the function f(x).

<h3>How to solve the question?</h3>

In the question, we are asked to find the function value for the function f(x) = 3x² + 2x - 6 for:

a. f(0)

b. f(2)

c. f(-4)

d. f(b)

e. f(4a).

We calculate these in the following ways:-

a. f(0):

We substitute the value of x = 0 in the function f(x).

Therefore f(0) = 3(0)² + 2(0) - 6,

or, f(0) = 0 + 0 - 6 = -6.

Therefore, the function value f(0) for the function f(x) = 3x² + 2x - 6 is <u>-6</u>.

b. f(2):

We substitute the value of x = 2 in the function f(x).

Therefore f(2) = 3(2)² + 2(2) - 6,

or, f(2) = 12 + 4 - 6 = 10.

Therefore, the function value f(2) for the function f(x) = 3x² + 2x - 6 is <u>10</u>.

c. f(-4):

We substitute the value of x = -4 in the function f(x).

Therefore f(-4) = 3(-4)² + 2(-4) - 6,

or, f(-4) = 48 - 8 - 6 = 34.

Therefore, the function value f(-4) for the function f(x) = 3x² + 2x - 6 is <u>34</u>.

d. f(b):

We substitute the value of x = b in the function f(x).

Therefore f(b) = 3(b)² + 2(b) - 6,

or, f(b) = 3b² + 2b - 6.

Therefore, the function value f(b) for the function f(x) = 3x² + 2x - 6 is <u>3b² + 2b - 6</u>.

e. f(4a):

We substitute the value of x = 4a in the function f(x).

Therefore f(4a) = 3(4a)² + 2(4a) - 6,

or, f(0) = 48a² + 8a - 6.

Therefore, the function value f(0) for the function f(x) = 3x² + 2x - 6 is <u>48a² + 8a - 6</u>.

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Evaluate: xy+2x^2, if x=0.1 and y=9.8

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Answer: 1

Step-by-step explanation:

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3 years ago

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