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2 years ago

This is a complemntary angle. Solve for X

Mathematics

1 answer:

just olya [345]2 years ago

7 0

Answer:

x = 30

Step-by-step explanation:

We start off with 90 degrees

2x + x = 90

Add all like terms

3x = 90

Divide 3 on both sides

$\frac{3x} {3} = \frac{90} {3}$

x = 30

To check your answer:

Let x be 30

2x + x = 90

2 (x 30) + 30 = 90

60 + 30 = 90

90 = 90

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An F5 tornado is classified as having mean wind speeds greater than 261 mph. In an effort to classify a recent tornado, 20 wind

Anna35 [415]

Answer:

Type 2 error

Step-by-step explanation:

H0 : μ = 261

H0 : μ > 261

By failing to reject H0 ; when the it is false. This means accepting null hypothesis when it is actually FALSE. Then a type 2 error has been committed.

This is different from a type 1 error whereby the null hypothesis is rejected when it is actually TRUE.

Hence, by finding no evidence to reject the null hypothesis during statistical testing when the actual windspeed of an F5 tornado during statistical testing is actually greater than 261 mph.

6 0

2 years ago

A coin is to be tossed as many times as necessary to turn up one head. Thus the elements c of the sample space C are H, TH, TTH,

slavikrds [6]

Answer:

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is $\frac{1}{2}$ , in the second is $\frac{1}{4}$ , in the third is $\frac{1}{8}$ and so on. Then, P(C) is given by the next sum:

$P(C)=\sum^{\infty}_{n=1}(\frac{1}{2} )^{n}=1$

This is a geometric series with factor $\frac{1}{2}$ . Then is convergent to $\frac{1}{1-\frac{1}{2}}-1=1.$ . With this we have proved that P(C)=1.

Now, observe that

$P(H)=\frac{1}{2}, P(TH)=\frac{1}{4},P(TTH)=\frac{1}{8},P(TTTH)=\frac{1}{16},P(TTTTH)=\frac{1}{32},P(TTTTTH)=\frac{1}{64}.$

Then

$P(C1)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} =\frac{31}{32}$

$P(C2)=P(TTTTH)+P(TTTTTH)=\frac{1}{32}+\frac{1}{64} =\frac{3}{64}$

$P(C1\cap C2)=P(TTTTH)=\frac{1}{32}$

and

$P(C1\cup C2)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)+P(TTTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} +\frac{1}{64}=\frac{63}{64}$

5 0

2 years ago

PLEASE HELP! I HAVE A TIME LIMIT AND IM BEHIND

Kipish [7]

Answer:

Part A none

Part B drawn

Step-by-step explanation:

Suppose the transversal intersects a pair of parallel lines it creates two pairs of alternate exterior angles.

Now if we look at the first figure we find that the alternate exterior angle 1 and 4 are equal . Also 3 and 2 are equal.

But <1 and < 2 are not equal . They are supplementary angles. Their sum is equal to 180 degrees.

Similarly angles 3 and4 are supplementary angles.

This situation does not support Ricky's claim. So you will select none in part A.

Now in part B we see that angle 5 &8 are equal and 6 & 7 are congruent.

This refutes Ricky's claims and this can be proved mathematically.

Angles 5 & 6 are supplementary angles. Similarly 7 & 8 are supplementary therefore they cannot be equal as they are unequal and a transversal is drawn not a perpendicular.

3 0

2 years ago

PLEASE HELP!! ILL MARK BRAINLYEST!!!

Liula [17]

Answer:

The answer is 144 m 2, hope this helps!!!:)

3 0

2 years ago

7/12 + 3/4 in simplest form?

Mariulka [41]

Well first we have to add 7/12 and 3/4 together which is 7/12+3/4=4/3. Now we have to reduce that to simplest form. Which would be 1 1/3 is 7/12+3/4 in simplest form!

4 0

3 years ago

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