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3 years ago

5 over 12= x+1 over 4 please help!

Mathematics

2 answers:

ASHA 777 [7]3 years ago

6 0

5/12 = x + 1/4

Lets Solve your Equation:

5/12 = x + 1/4

Step 1: Flip the Equation:

x + 1/4 = 5/12

Step 2: Subtract 1 / 4 From Both Sides:

x + 1/4 - 1/4 = 5/12 - 1/4

x = 1/6

Answer: x = 1/6, (Decimal: x ===> 0.166667).

Hope that helps!!!! : )

SCORPION-xisa [38]3 years ago

3 0

5/12=x+1/4

Equals 1/6

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If i have to round my meam to the nearest tenth how do i do that?

Vladimir [108]

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8 0

3 years ago

the ratio of sallys height is 7:8. if the sum of their heights is 90 inches. how tall are sally and jack?

pickupchik [31]

Answer:

Sally is 42 in. tall, and Jack is 48 in. tall.

Step-by-step explanation:

There are some words missing in the problem.

Perhaps the problem was meant to read:

"The ratio of Sally's height to Jack's height is 7:8. If the sum of their heights is 90 inches, how tall are Sally and Jack?"

Solution:

The ratio of the heights is 7:8.

Sally could measure 7 inches and Jack 8 inches, but then when you add the heights, 7 in. + 8 in. = 15 in. which is not 90 inches.

If you multiply both numbers in a ratio by the same number, the new numbers are still in the same ratio.

Multiply 7 and 8 by 2. You get 14 and 16. Maybe Sally is 14 in. tall and Jack is 16 in. tall. Add the heights, 14 in. + 16 in. = 30 in. This is also not 90 in.

We can keep on guessing what number to multiply by 7 and 8 by so their sum is 90, but we can use algebra to write an equation and not have to go through many guesses.

There is a number, x, that when you multiply 7 and 8 by x, the sum of the products is 90. We don't know what x is, but we can write an equation and solve for x.

The numbers in the ratio are 7x and 8x.

7x and 8x are still in the ratio 7:8.

Now we add the numbers 7x and 8x and set the sum equal to 90. Then we solve for x.

7x + 8x = 90

15x = 90

x = 6

We get x = 6. Now we know we need to multiply both 7 and 8 by 6 to get the heights we need.

7 in. * 6 = 42 in.

8 in. * 6 = 48 in.

Check: 42 in. + 48 in. = 90 in.

Answer: Sally is 42 in. tall, and Jack is 48 in. tall.

7 0

3 years ago

Jonathan ran five days a week. The most he ran in one day was 3.5 miles. Write an inequality that shows the distance jonathan co

natka813 [3]

Answer: $x\leq17.5$

Step-by-step explanation:

Given: The number of days Jonathan ran = 5

The most he ran in 1 day = 3.5 miles

Therefore, the maximum distance he ran in a week= $5\times3.5=17.5\ miles$

Let x be the distance Jonathan could have rum in a week, such that

$x\leq17.5$

Hence, the required inequality is $x\leq17.5$ .

8 0

3 years ago

Read 2 more answers

We would like to use the power series method to find the general solution to the differential equation d 2y dx2 − 4x dy dx + 12y

Feliz [49]

$y=\displaystyle\sum_{n\ge0}a_nx^n$

$\dfrac{\mathrm dy}{\mathrm dx}=\displaystyle\sum_{n\ge1}na_nx^{n-1}\implies4x\dfrac{\mathrm dy}{\mathrm dx}=4\sum_{n\ge1}na_nx^n=4\sum_{n\ge0}na_nx^n$

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}=\sum_{n\ge0}(n+2)(n+1)a_{n+2}x^n$

Substituting into the ODE

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-4x\dfrac{\mathrm dy}{\mathrm dx}+12y=0$

gives

$\displaystyle\sum_{n\ge0}\bigg((n+2)(n+1)a_{n+2}-4na_n+12a_n\bigg)x^n=0$

so that the coefficients of the series are given according to

$\begin{cases}a_0=y(0)\\a_1=y'(0)\\a_{n+2}=\dfrac{4(n-3)a_n}{(n+2)(n+1)}&\text{for }n\ge0\end{cases}$

We can shift the index in the recursive part of this definition to get

$a_n=\dfrac{4(n-5)a_{n-2}}{n(n-1)}$

for $n\ge2$ . There's dependency between coefficients that are 2 indices apart, so we can consider 2 cases:

If $n=2k$ , where $k\ge0$ is an integer, then

$k=0\implies n=0\implies a_0=a_0$

but since $y(0)=0$ , we have $a_0=0$ and $a_{2k}=0$ for all $k\ge0$ .

If $n=2k+1$ , then

$k=0\implies n=1\implies a_1=a_1$

$k=1\implies n=3\implies a_3=\dfrac{4(-2)a_1}{3\cdot2}=-\dfrac43a_1$

$k=2\implies n=5\implies a_5=0$

and so $a_{2k+1}=0$ for all $k\ge2$ . If $y'(0)=1$ , we then have $a_1=1$ and $a_3=-\dfrac43$ .

So the ODE has solution

$y(x)=\displaystyle\sum_{k\ge0}(a_{2k}x^{2k}+a_{2k+1}x^{2k+1})\implies\boxed{y(x)=x-\dfrac43x^3}$

8 0

3 years ago

Complete the square 3x^2+12x=15

barxatty [35]

Step-by-step explanation:

$3 {x}^{2} + 12x = 15 \\ 3 ({x}^{2} + 4x) = 15 \\ {x}^{2} + 4x = 5 \\ {x}^{2} + 4x = 5 \\ {x}^{2} + 4x + 4 = 5 + 4 \\ {x}^{2} + 4x + 4 = 9 \\ {x}^{2} + 4x + {2}^{2} = {3}^{2} \\ \red{ \bold{ (x + 2)^{2} = {3}^{2}}} \\$

3 0

4 years ago