1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goblinko [34]
3 years ago
12

Solve for w - 2w - 7 = 9

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

-2w−7=9

1 Add 7 to both sides.

-2w=9+7

2 Simplify 9+7 to 16

-2w=16

3 Divide both sides by -2

w= -16/2

w= - 8

liberstina [14]3 years ago
3 0

Step-by-step explanation:

-2w=9+7

-2w=16

w=16/-2

w=-8

You might be interested in
Solve for x.
Leto [7]

Answer:

x < 4

Step-by-step explanation:

Step 1: Subtract 10 from both sides.

  • -8x + 10 - 10 > -22 - 10
  • -8x > -32

Step 2: Divide both sides by -8 and flip the inequality sign.

  • \frac{-8x}{-8} > \frac{-32}{-8}
  • x < 4

Therefore, the answer is x < 4.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0
2 years ago
At Stephanie's new job, she spent $6.50, $8, $7.25, $13.50, and $9.75 on lunch the first week. In the second week, Stephanie spe
MaRussiya [10]

Answer:

The mean for the second week is $2 less than the first and in percentage it is 22% less.

Step-by-step explanation:

The mean is given by the sum of all individual values divided by the number of values. For the first week the sum is:

sum1 = 6.5 + 8 + 7.25 + 13.5 + 9.75

sum1 = 45

Since she spent 10 less in the second week the sum is:

sum2 = sum1 - 10 = 45 - 10 = 35

The mean for each week is:

mean1 = sum1/5 = 45/5 = 9

mean2 = sum2/5 = 35/5 = 7

difference = mean1 - mean2 = 9-7 = 2

difference(%) = [2/9]*100 = 0.22*100 = 22%

The mean for the second week is $2 less than the first and in percentage it is 22% less.

6 0
3 years ago
1. 8 - n = -4
iogann1982 [59]

Answer:

1.-n=-12; n=12

2.18=-2x; x=-9

3.-n=-12; n=12

4.b=3


4 0
3 years ago
24% students in a clan were absent in a day .If 38 students were present ,what is the total strength in the clan
Lemur [1.5K]

Answer:

50 students

Step-by-step explanation:

24% students in a clan were absent in a day .

Hence, the Percentage of students present is calculated as:.

= 100 % - 24 %

= 76%

From the question, we know that:

If 38 students were present ,what is the total strength in the clan

The total strength of the clan = Total number of students. This is calculated as:

76% × x = 38 students.

76/100 × x = 38

76x /100 = 38

Cross Multiply

76x = 38 × 100

x = 3800/76

x = 50 students

5 0
3 years ago
The quadrilateral shown is a rhombus. If AB = 17 and AE = 8, what is the measure of AC? A) 8 B) 12 C) 16 D) 24
Contact [7]

Answer:

C)16

Step-by-step explanation:

assuming the rhombus is named ABCD and E is where the diagonals meet.

Rhombus is a quadrilateral in which

  • All sides are equal
  • Opposite internal angles are equal
  • Diagonals bisect each other at right angles

As rhombus is  ABCD , AC is a diagonal which is bisected by E (According to the properties of Rhombus)

therefore AC will be twice of AE which is given to be 8

⇒ Answer is 16

5 0
3 years ago
Read 2 more answers
Other questions:
  • the number of dogs at the shelter is a two digit, odd number. it is more than 80 . the tens digit is less than the ones digits.
    13·1 answer
  • PLEASE ANSWER I NEED HELP!
    7·1 answer
  • 2x+-3y · 6e<br> My friend needs to know it, it would be nice if you can answer it for him
    7·2 answers
  • Which pair of angles is supplementary? ∠RXZ and ∠YXZ ∠PXQ and ∠RXS ∠YZX and ∠UZT ∠WZX and ∠WYX
    8·2 answers
  • One vertex of an equilateral triangle is at the origin and the other vertex is at (3,4)
    12·2 answers
  • What is p(9)? i need help for my math work
    7·1 answer
  • Can anyone help me with 49 and 50 thank you
    5·1 answer
  • Please help me find the volume of the cone. See attached photo . Thank you !
    6·1 answer
  • Which fraction is equal to 0.13?
    12·2 answers
  • Solve the equation 4(c-3)-8
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!