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sesenic [268]
3 years ago
10

In a ___________, a random variable can take any value in a specified range.

Mathematics
1 answer:
goldenfox [79]3 years ago
5 0
The answer is "c. continuous probability distribution."

"Continuous" means it is a subset of the real numbers set: it can take any value in a specified range. For example, if you break at random a stick with a given length of 12 cm, and then measure the shortest piece, you can get any value in the range (0 cm, 6 cm). This is a continuous random variable.

A random variable is said to be "discrete" if it can only take values from a finite (or countably infinite) set. For example, if you roll a dice, you can get only 1, 2, ..., 6. But you cannot get any vaue in the range [1, 6], because the value must be an integer (e.g., you cannot get the vaue 2.5). This is a discrete random variable.

A somewhat technical explanation:

- A random variable is a mapping from a event space to a number set: it associates a number (a value of the variable) with every event.

- The random variable is said to be continuous if it maps events to numbers from a subset of the set of real numbers.

- The probability distributions corresponding to continuous random variables are called continuous probability distributions.
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I need help with question 3
agasfer [191]

Answer:

see explanation

Step-by-step explanation:

To find the y-intercept let x = 0, in the equation

6x - 3y = 15 → (1)

x = 0 : - 3y = 15 ⇒ y = - 5 ⇒ (0, - 5) ← y- intercept

x + 3y = - 8 → (2)

x = 0 : 3y = - 8 ⇒ y = -\frac{8}{3} ⇒ (0, - \frac{8}{3}) ← y- intercept


4 0
3 years ago
Part I
klemol [59]
It depends on the shape it may be rotation
6 0
3 years ago
I cant figure this out what is 2+2?<br> I keep getting fish and idk why plzzzz helpp
Misha Larkins [42]

Answer:

Seriously i know you r kidding its 4 for sure.

5 0
3 years ago
Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.
Anika [276]
For this case we have the following functions:
 h (x) = 2x - 5
 t (x) = 6x + 4

 Part A: (h + t) (x)
 (h + t) (x) = h (x) + t (x)
 (h + t) (x) = (2x - 5) + (6x + 4)
 (h + t) (x) = 8x - 1

 Part B: (h ⋅ t) (x)
 (h ⋅ t) (x) = h (x) * t (x)
 (h ⋅ t) (x) = (2x - 5) * (6x + 4)
 (h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
 (h ⋅ t) (x) = 12x ^ 2 - 22x - 20

 Part C: h [t (x)]
 h [t (x)] = 2 (6x + 4) - 5
 h [t (x)] = 12x + 8 - 5
 h [t (x)] = 12x + 3
6 0
3 years ago
Work out m and c for the line: y = x − 6
Nataly [62]

Answer:

As y = mx + c (standard form)

Thus relating the equation , we get

m = 1

c = -6

8 0
3 years ago
Read 2 more answers
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