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3 years ago

The following two-way table describes student's

Mathematics

1 answer:

Irina-Kira [14]3 years ago

7 0

Answer:

$P(Sports|Senior)= 0.71$

Step-by-step explanation:

Hello!

You have a two-way table with the information describing students after school activities regarding the grade the student is in.

You have to calculate the probability that a randomly selected student is ins sports given that he is a senior.

This is a conditional probability and you can symbolize it as:

P(Sports|Senior)

Using the definition of the conditional probability we know that:

$P(Sports|Senior)= \frac{P(Sports n Senior)}{P(senior)}$

The probability of the intersection of both events "Sports" and "Seniors" can be calculated as the number of students that are in senior years and take sports by the total of students in the sample

P(Sports ∩ Senior)= $\frac{25}{100}= 0.25$

The probability of the student being a senior is a marginal probability, you can calculate is as the number of observed students that are in senior year by the total number of students:

P(senior)= $\frac{35}{100} = 0.35$

Now you can calculate the asked probability

$P(Sports|Senior)= \frac{P(Sports n Senior)}{P(senior)}= \frac{0.25}{0.35} = 0.71$

I hope this helps!

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Answer:

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Step-by-step explanation:

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Number of values in data class 1: n1=2

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Number of values in data class 5: n5=1

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