We know, volume of a Cube = Edge³
In short, Your Equation would be: v = f³
Hope this helps!
The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
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Answer: 97.0
Step-by-step explanation:
Let's assume that number as x
The product of 7 and a number =7x
and then increased by 1
so, it will become
=7x+1
now, it is between 15 and 43
so, we can write as

now, we can solve for x
Since, we have to isolate x
step-1:
Subtract all the sides by 1


step-2:
Divide all the sides by 7


so, solution is
.............Answer
Answer:
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ons are in the crayon box.If there are 4 rows of 19 crayons,