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mash [69]
3 years ago
10

Evaluate the expression. 12(43−6⋅32)

Mathematics
2 answers:
Mkey [24]3 years ago
7 0
If that's 6 time 32 its -1788

but if its 6.32
its 440.16
adoni [48]3 years ago
7 0
The answer is -1788. Hope this helps!
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Simplify<br> (x – 3) (232 – 4x – 7)
11111nata11111 [884]

Answer:

-4x^2 + 237x - 675

Step-by-step explanation:

(x - 3)*(232 - 4x -7)                            >> Distribute x and -3 to the trinomial

232x - 4x^2 - 7x - 696 + 12x + 21     >> Simplify

-4x^2 + 237x - 675

3 0
3 years ago
Read 2 more answers
Christopher works at the power plant for the southwest part of his home state. For peak operational performance, his department
Licemer1 [7]

Answer:

B) To maintain peak performance for every 50 generators, there are 10 inspectors.

Step-by-step explanation:

For peak operational:

3 electricians for each generator.  ⇒  1 Generator : 3 Electricians

4 inspectors for every 60 electricians. ⇒  60 Electricians : 4 Inspectors

Now, the number of generators the state has now = 50

Let us assume the number of  inspectors  required by the power plant  = m

Now, from the given ratios:

For, 3 electrician there  is 1 generator

⇒ For, 3 x 20 Electrician  there is 1  x 20 Generators.

or, for 60 Electrician there are 20 Generators.   (1)

Also, for 60 Electrician there are 4 inspectors.    (2)

⇒From (1) and (2), we get:

For every 20 generators, there are 4 inspectors.

And, from what we have assumed  For every 50 generators, there are m inspectors.

So, by the RATIO OF PROPORTION:

\frac{20}{4}  = \frac{50}{m}\\ \implies  m = 50 \times\frac{4}{20}  = 10

or, m = 10

Hence, to maintain peak performance for every 50 generators, there are 10 inspectors.

3 0
3 years ago
What is the area of the shaded portion of the circle?
SOVA2 [1]

Answer:

The first option is the correct one, the area of the shaded portion of the circle is

[/tex](5 \pi -11.6)ft^2[/tex]

Step-by-step explanation:

Let us first consider the triangle + the shadow.

The full area of the circle is the radius squared times pi, so

A=(5 ft)^2 \cdot \pi \\25 ft^2 \cdot \pi

Since \frac{72^{\circ}}{360^{\circ}}=\frac{1}{5}, the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus

A_1=\frac{1}{5}25 ft^2 \cdot \pi\\ =5 ft^2 \cdot \pi

If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from A_1.

The area of the triangle is given by

A_{triangle}=\frac{1}{2}\cdot (2.9+2.9)ft \cdot 4 ft\\= 11.6 ft^2

Thus the area of the shaded portion of the circle is

A_1-A_{triangle}=5 \pi ft^2-11.6ft^2\\= (5 \pi -11.6)ft^2

3 0
3 years ago
Halla de manera analítica las imágenes, los puntos de cortes y la tabla de valores de la
VLD [36.1K]
Do u want the answe for y= -x- 2/3
6 0
3 years ago
What is the volume of a cylinder with<br>a radius of 6 m and a height of 9 cm?<br>​
forsale [732]

Answer:

1,017.876

i hope this helpes

7 0
3 years ago
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