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RoseWind [281]
3 years ago
13

Write the standard form of the equation for:y+3=-3/2 (x+1)I will give Brainliest

Mathematics
2 answers:
raketka [301]3 years ago
3 0

Answer:

y+3= −3 2 (x+1)

y= −3 2 x+ −9 2

i think..

aniked [119]3 years ago
3 0

Answer: 3x- 2y=3

Step-by-step explanation:

You might be interested in
If A = 30° and r = 12, find x. (Round your answer to the nearest whole number.)
Margaret [11]

Answer:

\boxed{12}

Step-by-step explanation:

A = 30° and r = 12

\sin A = \frac{r}{r + x}

\sin 30 = \frac{12}{12 + x}

\frac{1}{2} = \frac{12}{12 + x}

1(12 + x) = 2(12)

12 + x = 24

x = 24 - 12

x = 12

.

Happy to help :)

6 0
3 years ago
Read 2 more answers
Drag each equation and coordinate to the correct location on the table. Not all equations or coordinates will be used. In the ta
Elena L [17]

Answer:

Standard Form           Equivalent Form            Extreme Values

y=x^2-6x+17                   (x-3)^2+8                        (3,8)

y=x^2+8x+21                  (x+4)^2+5                        (-4,5)

y=x^2-16x+60                 (x-8)^2-4                         (8,-4)

Step-by-step explanation:

1) Standard form:

y=x^2-6x+17

Equivalent Form:

Can be found using completing the square method.

y=x^2-6x+17\\y=x^2-2(x)(3)+(3)^2-(3)^2+17\\y=(x-3)^2-9+17\\y=(x-3)^2+8

So, Equivalent form is: (x-3)^2+8

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate is: 2x-6

Now, put the derivate equal to zero: 2x-6 = 0

2x=6\\x=6/3 \\x=3

Maximum value can be found by putting minimum value in the given function:

Put x = 3 and solve:

(3)^2-6(3)+17\\9-18+17\\9-1\\=8\\

So, the extreme values is: (3,8)

2) Standard form:

y=x^2+8x+21

Equivalent Form:

Can be found using completing the square method.

y=x^2+8x+21\\y=x^2+2(x)(4)+(4)^2-(4)^2+21\\y=(x+4)^2-16+21\\y=(x+4)^2+5

So, Equivalent form is: (x+4)^2+5

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate of x^2+8x+21 is: 2x+8

Now, put the derivate equal to zero:

2x+8 = 0\\2x=-8\\x=-8/2 \\x=-4

So, minimum value is: -4

Maximum value can be found by putting minimum value in the given function:

Put x = -4 and solve:

x^2+8x+21\\=(-4)^2+8(-4)+21\\=16-32+21\\=5

So, Maximum value is: 5

So, the extreme values is: (-4,5)

3) Standard form:

y=x^2-16x+60

Equivalent Form:

Can be found using completing the square method.

y=x^2-16x+60\\y=x^2-2(x)(8)+(8)^2-(8)^2+60\\y=(x-8)^2-64+60\\y=(x-8)^2-4

So, Equivalent form is: (x-8)^2-4

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate of x^2-16x+60 is: 2x-16

Now, put the derivate equal to zero:

2x-16 = 0\\2x=16\\x=16/2 \\x=8

So, minimum value is: 8

Maximum value can be found by putting minimum value in the given function:

Put x = 8 and solve:

x^2-16x+60\\=(8)^2-16(8)+60\\=64-128+60\\=-4

So, Maximum value is: -4

So, the extreme values is: (8,-4)

4 0
3 years ago
Read 2 more answers
If y=-2x^2+4x, what is the value of y when x=-3.
pentagon [3]
-30,
y = -2(-3)^2 + 4(-3)
y = -2(9) + (-12)
y = -18 + (-12)
y = -30
8 0
3 years ago
A tennis ball machine serves a ball vertically into the air from a a height of 2 feet, with an initial 110 feet per second. What
goblinko [34]

Thank you for posting your question here. I hope the answer below will help. 


Vo=110 feet per second 

h0=2 feet 

So, h(t) = -16t^2 +110t +2 

Take the derivative: h'(t) = 110 -32t 

The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. 

So, set h'(t)=0 and solve for t: 

0 = 110 -32t 

-110 = -32t 

t=3.4375 

t=3.44 seconds 


5 0
4 years ago
What is the mean absolute deviation for 2, 9, 1, 7, 8, and 9? 1 3 6 8
Vladimir [108]
The answer is

B. 3

100% Verified!

Hope This Helps!:)
6 0
3 years ago
Read 2 more answers
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