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HACTEHA [7]
3 years ago
9

Starting with number 0 on my calculator, I do a calculation in five steps. At each step, I either add 1 or multiply by 2. What i

s the smallest number that cannot be the final result?
Mathematics
1 answer:
alisha [4.7K]3 years ago
5 0

Answer:

assuming only positive integers, the answer is 1

Step-by-step explanation:

the smallest number that you can get by adding is:

  • start with 0
  • then add 1 = 1
  • add another 1 = 2
  • add another 1 = 3
  • add another 1 = 4
  • add another 1 = 5

but you can also multiply, and anything multiplied by 0 is 0:

  • start with 0
  • multiply by 2 = 0
  • multiply by 2 = 0
  • multiply by 2 = 0
  • multiply by 2 = 0
  • multiply by 2 = 0

The question does not say that we need to do any specific calculation, it only gives us 2 options and we can choose them as many times as we want.

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ikadub [295]

Answer:

y=4/3x-1/3

Step-by-step explanation:

m=y2-y1/x2-x1

fill in the two points for the y's and the x's

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8 0
3 years ago
Answer please lot's of points.
Svetlanka [38]

Answer:

t≈8.0927

Step-by-step explanation:

h(t) = -16t^2 + 128t +12

We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

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Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

t≈8.0927

The first is before the rocket is launched so the only valid answer is the second one

3 0
3 years ago
Read 2 more answers
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djyliett [7]

Answer:

v = 3 , 3/5

Step-by-step explanation:

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Can someone help please? I really don't understand this.
zhannawk [14.2K]

Answer:

i don't know

Step-by-step explanation:

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2 years ago
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Which of the following is equivalent to the expression below?
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I think the answer is a
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2 years ago
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