Answer:
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Let
x,y, and z the long sides of the triangle
we know that
x+y+z=170 ft------> equation 1
x/y=25/14----> y=14x/25------> equation 2
y/z=14/12-----> equation 3
x/z=25/12----> z=12x/25------> equation 4
substitute equation 2 and equation 4 in equation 1
x+[14x/25]+[12x/25]=170------> multiply by 25 both sides
25x+14x+12x=4250
51x=4250
x=4250/51
x=250/3
y=14x/25------> y=(250/3)*(14/25)----> y=140/3
z=12y/14-----> (140/3)*12/14----> z=40
Using Heron's formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
where s is the semiperimeter
s=170/2-----> s=85 ft
Area=√85*[85-250/3]*[85-140/3]*[85-40]
Area=9.22*[1.67]*[38.33]*[45]------> Area=26558.21 ft²
the answer is
26558.21 ft²
Answer:
let the number of cows = x
let the number of chickens = y
since there are 42 heads:
x + y = 42
and since a cow has 4 legs, and a chicken has 2
4x + 2y = 144
from first equation:
x + y = 42
x = 42 - y (now, we will substitute this in the second equation)
4(42 - y) + 2y = 144
168 - 4y + 2y = 144
2y = 168 - 144
2y = 24
y = 12
now, we know the number of chickens. we will replace y with 12 in the first equation since it is more simpler
x + 12 = 42
x = 30
So, there are 30 cows and 12 chickens
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