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3 years ago

What angle pair relationship is shown?

Mathematics

1 answer:

snow_lady [41]3 years ago

3 0

Answer:

hmmmmmmmmmmmm ( thanks heavily in mind) if I can remember correctly I'm pretty sure it would be c

Step-by-step explanation:

I done this question for

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Question 3

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

Big Brain

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2 years ago

Hiii how are you guys doing if you answer this I’ll give you points and make you brainly or what ever it’s called and how do you

baherus [9]

Answer:

Hi how is your day going?

Step-by-step explanation:

I have some jokes and I hope you like them.

Knock Knock.

Who's There?

Scold.

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2 years ago

Expand the binomial<br> <img src="https://tex.z-dn.net/?f=%28x-%5Cfrac%7B2%7D%7B5%7D%29%5E%7B2%7D" id="TexFormula1" title="(x-\f

kkurt [141]

Answer:

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1

If you have the expression:

$(x- \frac{2}{5})^{2}$

You can write the expression it in the following way:

$(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})$

Then, apply the distributive property:

$(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}$

Simplify the expression:

$(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})$

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

$(a-b)^2$

Its expanded form will be:

$(a-b)^2= a^2 -2ab + b^2$

$a = x$

$b =\frac{2}{5}$

$(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2$

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

3 0

3 years ago

What is the slope of the line passing through (-3, 5) and (5,-3)?

Delvig [45]

-1 is the answer to your question

8 0

3 years ago

Read 2 more answers

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h

Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that $r = 0.047$

$172000 in 2004

This means that $P(0) = 172000$

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

$P(t) = P(0)(1+r)^{t}$

$249000 = 172000(1.047)^{t}$

$(1.047)^{t} = \frac{249000}{172000}$

$\log{(1.047)^{t}} = \log{\frac{249000}{172000}}$

$t\log(1.047) = \log{\frac{249000}{172000}}$

$t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}$

$t = 8.05$

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

8 0

3 years ago