Question

A number from 0 to 9 is randomly selected and then a letter from A to D is randomly selected. What is the probability that the number 3 and a consonant are selected? Express as a fraction in simplest form.

Answer 1

Answer:

3/20

Step-by-step explanation:

First we must get the total amount of possibilities.

We have ten numbers(0 included) and 4 letters. 10 * 4 = 40, so 40 total possibilities.

Now, let's see how many possibilities we can have for this.

Consonants in the 4 letters are B, C, D. This means we have 3 possibilities, but we ACTUALLy have 6 since it could b then 3, or 3 then b for all the letters.

So, we end up having 6/40 which simplifies in to 3/20