Question

Solve the equation x^2+17x+12=-3x^2 to the nearest tenth.

Answer 1

Answer:

$x=-\frac{17}{8}+\frac{\sqrt{97} }{8}$ or $x=-\frac{17}{8}-\frac{\sqrt{97} }{8}$

Step-by-step explanation:

$x^2+17x+12=-3x^2$

Add $3x^2$ on both sides.

$x^2+17x+12+3x^2=-3x^2+3x^2$

$x^2+17x+12+3x^2=0$

Combine like terms;

$4x^2+17x+12=0$

Use the quadratic formula;

a=4

b=17

c=12

$x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(17)\frac{+}{}\sqrt{(17)^2-4(4)(12)} }{2(4)}$

$x=\frac{-17\frac{+}{}\sqrt{289-192} }{8}$

$x=\frac{-17\frac{+}{}\sqrt{97} }{8}$

$x=-\frac{17}{8}+\frac{\sqrt{97} }{8}$ or $x=-\frac{17}{8}-\frac{\sqrt{97} }{8}$