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Damm [24]
3 years ago
6

A baker touches a pie right after taking it out of the oven. Which statement best explains why the pie feels hot?

Chemistry
2 answers:
Lana71 [14]3 years ago
6 0
<span>The pie is going to be hot right when it comes out of the oven because the oven uses air to transfer heat. The air warms at the bottom of the oven and the air rises to the top of the oven where your food is. This is why any food is going to be hot right after you take it out of an oven.</span>
ValentinkaMS [17]3 years ago
3 0

Answer:

Molecules in the pie move faster than molecules in the skin, so heat is transferred to the skin.

Explanation:

B

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Solve the following problem. Give your answer to the correct number of significant figures. a. 20.0 meters x 0012.65 meters b. 0
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Explanation:

For multiplication or division, the rule is to count the number of significant figures in each number being multiplied or divided and then limit the significant figures in the answer to the lowest count.

a. 20.0 meters x 0012.65 meters

The numbers are;

20.0 (3 s.f) and 12.65 (4 s.f)

The multiplication gives; 253

Since 253 is already in 3 s.f, that's the answer.

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The numbers are;

002.5 (2 s.f), 103 (3 s.f), 3.50 (3 s.f) and 102 (3 s.f)

002.5 × 103 = 257.5 = 260 (2 s.f)

3.50 × 102 = 357 = 360 (2 s.f)

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3 years ago
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8 0
3 years ago
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** worth 20 points + brainliest **
Bad White [126]

Answer : The correct option is, (D) 83^oC

Solution :

Formula used :

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

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m = mass of water = 40 g

c = specific heat of water = 4.18J/g^oC      

\Delta T=\text{Change in temperature}  

T_{final} = final temperature = ?

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Now put all the given values in the above formula, we get the final temperature of water.

-1300J=40g\times 4.18J/g^oC\times (T_{final}-91.0^oC)

T_{final}=83.2^oC\approx 83^oC

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Aqueous potassium bromide reacts with aqueous silver nitrate AgNO3 to form aqueous potassium nitrate KNO3 and solid silver bromi
ddd [48]
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 KBr (aq) + AgNo3  → KNO3(aq)  + AgBr(s)

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