Answer:
The molarity of the solution is 1.1 
Explanation:
Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
Molarity is expressed in units
In this case
- number of moles of solute= 0.564 moles
- volume= 0.510 L
Replacing:
Solving:
molarity= 1.1
<u><em>The molarity of the solution is 1.1 </em></u><u><em></em></u>
Answer:
185.05 g.
Explanation
Firstly, It is considered as a stichiometry problem.
From the balanced equation: 2LiCl → 2Li + Cl₂
It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.
We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.
n = (30.3 g) / (6.941 g/mole) = 4.365 moles.
Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.
Using cross multiplication:
2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.
??? moles of LiCl → 4.365 moles of Li.
The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.
Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).
Molar mass of LiCl = 42.394 g/mole.
mass = n x molar mass = (4.365 x 42.394) = 185.05 g.
All of the above is the answer
Answer:
We need 8.7 mL of the stock solution
Explanation:
Step 1: Data given
Volume of the solution he wants to prepare = 50.0 mL = 0.050 L
Concentration of the solution he wants to prepare = 0.80 M
The concentration of the stock solution = 4.6 M
Step 2: Calculate the volume of the stock solution
C1*V1 = C2*V2
⇒with C1 = the concentration of the stock solution = 4.6 M
⇒with V1 = the volume of the stock solution = TO BE DETERMINED
⇒with C2 = the concentration of the prepared solution = 0.80 M
⇒with V2 = the volume of the prepared solution = 0.050 L
4.6 M * V2 = 0.80 M * 0.050 L
V2 = (0.80 M * 0.050 L) / 4.6M
V2 = 0.0087 L = 8.7 mL
We need 8.7 mL of the stock solution
Answer:
1. C. distillation
2. B. conversion of mechanical energy into nuclear energy
3. B. Alpha ray
Explanation:
