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Agata [3.3K]
3 years ago
8

** worth 20 points + brainliest **

Chemistry
1 answer:
Bad White [126]3 years ago
5 0

Answer : The correct option is, (D) 83^oC

Solution :

Formula used :

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

Q = heat released = -1300 J

m = mass of water = 40 g

c = specific heat of water = 4.18J/g^oC      

\Delta T=\text{Change in temperature}  

T_{final} = final temperature = ?

T_{initial} = initial temperature = 91.0^oC

Now put all the given values in the above formula, we get the final temperature of water.

-1300J=40g\times 4.18J/g^oC\times (T_{final}-91.0^oC)

T_{final}=83.2^oC\approx 83^oC

Therefore, the final temperature of the water is, 83^oC

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