3 years ago

Geometry help please!

Mathematics

1 answer:

Mariulka [41]3 years ago

6 0

Answer:

1.20

2.6

3.Angle A is 20

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20= -x + (x squared)<br><br> solve for x

MArishka [77]

Answer:

Step-by-step explanation:

x = 5

x= -4

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−10x + 6(x − 5) = 12x − 62

tankabanditka [31]

Answer:

$x=2$

Step-by-step explanation:

So we have:

$-10x+6(x-5)=12x-62$

Distribute:

$-10x+6x-30=12x-62$

Combine like terms:

$-4x-30=12x-62$

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3 years ago

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X^2=4x-15 solve with Quadratic formula

bulgar [2K]

Answer:

$x=2+i\sqrt{11}$

$x=2-i\sqrt{11}$

Step-by-step explanation:

we have

$x^{2} =4x-15$ -------> $x^{2}-4x+15=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-4x+15=0$

$a=1\\b=-4\\c=15$

substitute in the formula

$x=\frac{-(-4)(+/-)\sqrt{-4^{2}-4(1)(15)}} {2(1)}$

$x=\frac{4(+/-)\sqrt{16-60}} {2}$

Remember that

$i=\sqrt{-1}$

$x=\frac{4(+/-)\sqrt{-44}} {2}$

$x=\frac{4(+/-)2i\sqrt{11}} {2}$

$x=\frac{4(+)2i\sqrt{11}}{2}=2+i\sqrt{11}$

$x=\frac{4(-)2i\sqrt{11}}{2}=2-i\sqrt{11}$

7 0

3 years ago