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yarga [219]
3 years ago
9

What is the simplified version of −(−3)2−−−−−−√?

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0
6+1ty is the best thing to do with this
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What is as 8 hundred is 8 thousand
Irina-Kira [14]
Not quite understand the question. We assume that the issue of ratios of numbers of 800 and 8000.
 Then 800 is one-tenth of the 8,000 800 other words is 10% of 8000.
Conversely, 8000 it ten times at 800 and 1000% of 800.
5 0
4 years ago
Simplify: 6x3y2 (4x4 − 3xy)
Over [174]
The answer is going to be: (2•3x^4y^2) • (4x^3<span> - 3y)

^=The variable or number behind it is an exponent 

</span>
8 0
3 years ago
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SOMEONe!! I suck at math and need help!!
Elina [12.6K]

<em>The volume is 117.438</em>

<em>To find volume you have multiply Length x Width x Height, so in this case it would be 4.6 x 3.7 x 6.9 = 117.238</em>

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8 0
3 years ago
The intensity of an earthquake with a magnitude of 2 is how many times greater than the intensity of an a standard earthquake ?
Ksju [112]

Answer:  

The intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of a standard earthquake.

Explanation:  

The magnitude of earthquakes is given by

Magnitude=log\frac{I}{S}

2=log\frac{I}{S}\\

Where I is the intensity of earthquake and S is the intensity of standard earthquake.

The magnitude of standard earthquakes is given by

Magnitude=log\frac{S}{S}= log(1) = 0

So comparing the magnitude of the given earthquake and standard earthquake,

log\frac{I}{S} = log\frac{S}{S}

log\frac{I}{S} - log\frac{S}{S}

log(2) - log(1)

2 - 0

2

which means that

10^2 = 100 times greater

Therefore, the intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of a standard earthquake.

6 0
3 years ago
Math! help!! will mark brainliest!! due today!!
MariettaO [177]
6 hours is 3
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8 hours is 7
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