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3 years ago

Austin has $5 more than Mark. If Mark has Δ dollars, write an expression for the amount of money Austin has.

Mathematics

2 answers:

elixir [45]3 years ago

7 0

Mark+5=austin
hope this helps
- turtles12345

Scrat [10]3 years ago

7 0

Answer:

Δ+ 5

Step-by-step explanation:

Since Austin has more money than Mark, add 5 to the amount Mark has. Austin has Δ+ 5 dollars.

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How many solutions does the following equation have? -3u=-3u-10

olga2289 [7]

Answer:

There are no solutions

Step-by-step explanation:

-3u=-3u-10

Add 3u to each side

-3u+3u=-3u+3u-10

0 = -10

This is never true so there are no solutions

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3 years ago

1.What are the values of the 6s in 36,621?

enot [183]

1) The value of 6s in 36,621 are 6,000 and 600.

first 6 is in the thousands place value while the second 6 is in the hundreds place value.
6 x 1000 = 6,000 and 6 x 100 = 600

2) The first 4 is ten times greater than the second 4 is shown in 354,426

the first 4 is in the thousands place value while the second 4 is in the hundreds place value
4 x 1000 = 4000 and 4 x 100 = 400

based on the question the first 4, which is 4000, is ten times greater than the second 4, which is 400.
we can check if this statement is true either by dividing 4000 by ten or multiplying 400 by ten.

4000/10 = 400 ; 400 x 10 = 4000. therefor, out of the 4 numbers given, the correct one is 354,426

3) The relationship of the two 5s in 552 is shown in 500 ÷ 50 = 10

based on its place value, the first five is in the hundreds place and the second five is in the tens place.

500 ÷ 50 = 10. This equation states that 500 is ten times greater than 50.

4) In 2,077 the first 7 is greater than the second 7 by 10 times.

using place value, first 7 is in the tens place while second 7 is in the ones place.

first 7 is 70; second 7 is 7. we divide 70 by 7 to know how many number of times 70 is greater than 7.

70 ÷ 7 = 10 times.

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3 years ago

A greater number than -8

sertanlavr [38]

Practically anything above -8
Such as -7, 2, 15600, anything not under -7.9

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2 years ago

Peter tracks the goals he scores in 9 soccer games. In two games Peter scored 2 goals each, in one game he scored 0 goals, in tw

Reika [66]

The average number of goals per game Peter scores, rounded to one decimal place is 1.6

<u><em>Explanation</em></u>

In first two games Peter scored 2 goals each. So, total score in two games = (2×2)= 4

In one game he scored 0 goal and in next two games he scored 3 goals each, so the total is (3×2)= 6

In the last four games he scored 1 goal in each, so the total is (1×4)= 4

So, the total score in all $9$ games $=4+0+6+4=14$

Thus, the average number of goals $= \frac{14}{9}= 1.5555....$

So, the average number of goals per game Peter scores, rounded to one decimal place is 1.6

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3 years ago

Read 2 more answers

Andrea Is selling candles as a fundraiser she spent $50 on supplies for making the candles she plans to sell candles for $10 eac

dalvyx [7]

COMPLETE QUESTION:

Andrea is selling candles as a fundraiser. She spent $50 on supplies for making the candles. She plans to sell the candles for $10 each. Her profit can be modeled by C(x) = 10x - 50.

What type of function is this?

What is the domain and range of the function?

Answer:

- This function is one-to-one

- Domain D = {x: x is a whole number ≤ Z}

- Range R = {y: y is in -50, ..., (10Z - 50)}

Where Z is the number of candles she could produce with $50.

Step-by-step explanation:

Given that her profit is modeled by C(x) = 10x - 50

- This function is one-to-one, because it is in the form f(x) = y.

Let the number of candles she could make with $50 be Z.

Then the domain is the set of all whole numbers less or equal to Z.

D = {x: x is a whole number ≤ Z}

If there are infinite number of candles she could make with that money, then

D = (-infinity, infinity)

When x = 0, we have C = -50

When x = Z, we have C = 10Z - 50

The range is then given as

R = whole numbers from -50 up to (10Z - 50)

R = {y: y is in (50 -Z), ..., (10Z - 50)}

If there are infinite number of candles she could make with that money, then

R = (-infinity, infinity)

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3 years ago