The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the
distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 2 to t = 5 represent?\
1 answer:
Answer:
The rate of change determines the average speed of the ball when it is dropped from the building.
Step-by-step explanation:
d(t) = 16t^2
when t = 2
d(t) = 16 (2)²
d(t) = 64
when t = 5
d(t) = 16 (5)²
d(t) = 400
Average speed/rate of change = distance/time = 64/2 = 32 feet
Average speed/rate of change = distance/time = 400/5 = 80 feet
The rate of change determines the average speed of the ball when it is dropped from the building.
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Step-by-step explanation:
Step-by-step explanation:
10 feet = 1 inch
50 feet = 5 inches
Do the same thing for the length.
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50/10 = 5
1/10 = x/50
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x = 50/10
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A. 4 dimes and 1 penny because it equal 41 cents, 7 nickels and 6 pennies equal 41 cents too
4x - 7 < 17
+ 7 + 7
4x < 24
4 4
x < 6
Solution Set: (6, ∞) and {x|x < 6}