The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the
distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 2 to t = 5 represent?\
1 answer:
Answer:
The rate of change determines the average speed of the ball when it is dropped from the building.
Step-by-step explanation:
d(t) = 16t^2
when t = 2
d(t) = 16 (2)²
d(t) = 64
when t = 5
d(t) = 16 (5)²
d(t) = 400
Average speed/rate of change = distance/time = 64/2 = 32 feet
Average speed/rate of change = distance/time = 400/5 = 80 feet
The rate of change determines the average speed of the ball when it is dropped from the building.
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