Hello!
For this problem we are given that quadrilateral ABCD is congruent to quadrilateral GJIH, meaning that all sides and angle measures will be equivalent to its corresponding side.
This means that to find
, we can look at quadrilateral GJIH's corresponding side to quadrilateral ABCD's side AD, which is side GH, which has a value of 9.
This means that 9 should also be the side length of side AD, which we're given a value of
.

Solve.

Hope this helps!
Answer:
0.40d
d - 0.60d
Step-by-step explanation:
d - 0.60
This doesn't work because it wants 60<em><u>%</u></em> 0.60 without the percent is a decimal number, and is not 60% of d.
100% - 60% = 40%
0.40d works because it is multiplying 0.40 and d which is also 40%.
d - 0.60d works because it is multiplying 0.60 and d which is also 60% and then subtract it from d.
0.60d doesn't work because it want the discounted price not the discount.
1 - 0.60d doesn't work because we don't know that d = 1, so it is subtracting the discount from 1 not d.
You replace z with 17
51-17=34
the answer is 34
Furthest from 0, so I am going to take the absolute value of these numbers. The absolute value will tell us how far away from 0 these numbers are.
|-1/2| = |- 0.5| = 0.5
|8/9| = |0.88| = 0.88
|0.2| = 0.2
so the number furthest from 0 is 8/9
You haven't told me what the question is. But I put the mouse
to my forehead, closed my eyes, took a deep breath, and I could
see it shimmering in my mind's eye. It was quite fuzzy, but I think
the question is
"What score does Andrew need on the next test
in order to raise his average to 72% ?"
The whole experience drew an incredible amount of energy
out of me, and the mouse is a total wreck. So we'll just go ahead
and answer that one. I hope it's the correct question.
The average score on 4 tests is
(1/4) (the sum of all the scores) .
In order for Andrew to have a 72% average on 4 tests,
the sum of the 4 scores must be
(4) x (72%) = 288% .
Out of that total that he needs, he already has
(64% + 69% + 73%) = 206%
on the first three tests.
So in order to average 72% for all 4 tests,
he'll need to score
(288% - 206%) = 82%
on the fourth one.