Question

Determine the non-permissible value(s) of the variable(s).

Answer 1

Answer:

i) the value of a = 0 is non-permissible

ii) the value of b = 0 is non-permissible

Step-by-step explanation:

i) the given expression is $\frac{5a^{2} + 80a }{50ab^{2} }$

ii) if a = 0 then the expression will become infinity hence the value of a = 0 cannot be used

iii) if b = 0 then the expression will become infinity, hence the value of b = 0 also cannot be used.

iv) In the numerator of the expression if it is factorized we get 5a$\times$ ( a + 16)

    if a = -16 then the value of the expression becomes zero.