All categories

3 years ago

How can you check the solution of an equation?

2 answers:

4 0

In order to check you would plug in the value of x and see if it equals the same thing.
or do the opposite of the equation. it depends on if you are dealing with x or not. so if you have 6-3 is 3 you can do 3+3 is 6

vagabundo [1.1K]3 years ago

4 0

Look at the left hand side of equation and if given number matches
do the same for the right hand
see if numbers match

You might be interested in

Help pls it's urgent. I would greatly appreciate it.

Damm [24]

Answer:

I think its 3 but i might be wrong

Step-by-step explanation:

Hope this helps

4 0

3 years ago

Read 2 more answers

In the first 3 games of his basketball season, Kevin scored 12, 17, and 10 points. His goal was to have a mean score of 14 point

olasank [31]

Its B) 14 yourwelco.e

7 0

4 years ago

Read 2 more answers

Y = -4x + 8<br> Y=3/5x - 6/5

VladimirAG [237]

Answer:

x=2 and y=0

Step-by-step explanation:

Rewrite equations:

y=−4x+8;y=

−6

Step: Solvey=−4x+8for y:

y=−4x+8

Step: Substitute−4x+8foryiny=

−6

−4x+8=

−6

−4x+8+

−3

−6

−3

x(Add (-3)/5x to both sides)

−23

x+8=

−6

−23

x+8+−8=

−6

+−8(Add -8 to both sides)

−23

−46

−23

−46

−23

(Divide both sides by (-23)/5)

x=2

Step: Substitute2forxiny=−4x+8:

y=−4x+8

y=(−4)(2)+8

y=0(Simplify both sides of the equation)

5 0

3 years ago

The first quartile of a data set is 72, and the third quartile is 92. Which of these values in the data set is an outlier ?

konstantin123 [22]

Answer: Option D

D. 41

Step-by-step explanation:

A value $x_i$ is considered an outlier if

$x_i> Q_3 + 1.5IQR$

$x_i$

Where

$Q_3$ is the third quartile

$Q_1$ is the first quartile

IQR is the interquartile range.

$IQR = Q_3-Q_1$

In this case:

$Q_3=92\\Q_1=72$

$IQR = 92-72 =20$

$Q_3 + 1.5IQR = 92 + 1.5*20 = 122$

$Q_1 - 1.5IQR=72-1.5*20=42$

Then the outlier values will be all those greater than 122 or less than 42

Therefore the answer is the option D.

8 0

3 years ago

The length of a rectangle picture frame is 2 centimeters more than twice it’s width. If the area of the frame is 364 square cent

sergeinik [125]

Answer:

Length:28 cm

Width: 13 cm

Step-by-step explanation:

Let

x ---> the length of a rectangle picture frame

y ---> the width of a rectangle picture frame

we know that

The area of a rectangle picture frame is equal to

$A=xy$

we have

$A=364\ cm^2$

$364=xy$ ----> equation A

The length of a rectangle picture frame is 2 centimeters more than twice it’s width

$x=2y+2$ ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (28,13)

see the attached figure

therefore

Length:28 cm

Width: 13 cm

5 0

3 years ago