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3 years ago

What is a frequency table

Mathematics

2 answers:

Verizon [17]3 years ago

6 0

Answer: its a method or organizing your info while displaying it

Step-by-step explanation:

stiv31 [10]3 years ago

4 0

Answer:

A frequency distribution is a list,table or graph that displays the frequency of various outcomes in a sample.hope this helps you .

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What is the surface area of the square pyramid? 3 A 2 6 square units

stich3 [128]

Answer:

≈ 16.65 un²

Step-by-step explanation:

The image shows the formula

With the given info you would get ≈ 16.65 un²

5 0

3 years ago

1000000+200000=? fun for me

Arturiano [62]

Answer:

1,200,000

Step-by-step explanation:

hope i helped

6 0

3 years ago

What is the inverse of the function f(x) = 2x – 10?

Gala2k [10]

$\bf f(x)=\boxed{y}=2\boxed{x}-10\qquad inverse\implies =\boxed{x}=2\boxed{y}-10\impliedby f^{-1}
\\\\\\
x+10=2y\implies \cfrac{x+10}{2}=y\implies \cfrac{x}{2}+\cfrac{10}{2}=y
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\cfrac{x}{2}+5=y=f^{-1}(x)$

4 0

3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

Read 2 more answers

Answer this????????????

goldenfox [79]

Answer:

$a + b = 8 \\ 3a - 4b = 3 \\ 4a + 4b = 32 \\ 3a - 4b = 3 \\7a = 35 \\ (a = 5 )\: and \: (b = 3)$

8 0

3 years ago