the ball thrown off course was
° .
<u>Step-by-step explanation:</u>
Here we have , A ball is dropped from the top of a 45 foot building. Once the ball is released, a gust of wind blows the ball off course and is dropped 4 feet from the base of the building. We need to find that How many degrees was the ball thrown off course? Let's find out:
Basically above given condition is a case of right angled triangle with following parameters
![Perpendicular = 4 ft](https://tex.z-dn.net/?f=Perpendicular%20%3D%204%20ft)
![Base = 45 ft](https://tex.z-dn.net/?f=Base%20%3D%2045%20ft)
x = angle between Perpendicular & base
Now , ![tanx = \frac{Perpendicular}{base}](https://tex.z-dn.net/?f=tanx%20%3D%20%5Cfrac%7BPerpendicular%7D%7Bbase%7D)
⇒ ![tanx = \frac{Perpendicular}{base}](https://tex.z-dn.net/?f=tanx%20%3D%20%5Cfrac%7BPerpendicular%7D%7Bbase%7D)
⇒ ![tanx = \frac{4}{45}](https://tex.z-dn.net/?f=tanx%20%3D%20%5Cfrac%7B4%7D%7B45%7D)
Taking tan inverse both sides , in order to obtain x :
⇒ ![tan^{-1}(tanx) = tan^{-1}(\frac{4}{45})](https://tex.z-dn.net/?f=tan%5E%7B-1%7D%28tanx%29%20%3D%20tan%5E%7B-1%7D%28%5Cfrac%7B4%7D%7B45%7D%29)
⇒ ![x = tan^{-1}(\frac{4}{45})](https://tex.z-dn.net/?f=x%20%3D%20tan%5E%7B-1%7D%28%5Cfrac%7B4%7D%7B45%7D%29)
⇒ ![x = tan^{-1}(0.08)](https://tex.z-dn.net/?f=x%20%3D%20tan%5E%7B-1%7D%280.08%29)
⇒
°
Therefore, the ball thrown off course was
° .
Answer:
y=12°
x= 20°
Step-by-step explanation:
5y=60
y=60/5=12
3x+60+60=180
3x=180-120=60
x=60/3=20
Answer:
A) 8
Step-by-step explanation:
Answer:
Solve it by teliing what X and Y is
Step-by-step explanation: