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Svetlanka [38]
3 years ago
5

Find the equation of the line that contains The given point and is perpendicular to the given line. Write the equation in slope

intercept form, if possible. (21,7); 7x-5y=6
​
Mathematics
1 answer:
mixer [17]3 years ago
8 0

Answer:

an = 63(-1/3)^(n-1)

Step-by-step explanation:

This is a geometric sequence with first term 63 and common ratio -1/3.

The equation for the nth term  is

an = 63(-1/3)^(n-1).

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Part A: Solve A = (x + 23) for x. (4 points) Part B: Determine the value of x when A = 108. (2 points) Part C: Solve -np - 90 &g
Galina-37 [17]
<span>Part A: Solve A = (x + 23) for x.

A = x + 23

=> A - 23 = x + 23 - 23

=> A - 23 = x

=> x = A - 23 <------- answer

Part B: Determine the value of x when A = 108

Replace the value of A in the expression x = A - 23

x = 108 - 23 = 75

x = 75 <------- answer

Part C: Solve -np - 90 > 30 for n.

-np - 90 > 30

=> -np + np - 90 >30 +  np

=> - 90 > 30 + np

=> -90 - 30 > 30 - 30 + np

=> -120 > np

=> np < - 120 <----- answer
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7 0
3 years ago
GOOD EVENING, FRIENDS, I WANT TO ASK ON THE ACCOUNT OF HIS NAME‏BENJEMIN360 . THIS ANSWERS ARE VERY WONDERFUL, BUT I CAN'T COMMU
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3 years ago
HELP PLEASE!! BRAINLIEST AND 10 POINTS!! if the sixth term of a geometric sequence is 224, and the eleventh term is 7168, what i
Klio2033 [76]
The first term should be 7

a1 = (224) / (2)6 - 1 = 7
8 0
3 years ago
The price of an mp3 player is reduced to three-fourths of its original price. The new price is $75. Find the original price of t
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Step-by-step explanation:


7 0
4 years ago
Which of the following is the equation of the line that is parallel to y=35x+8 y = 3 5 x + 8 and goes through point (-10,4)?
xeze [42]

Slope-intercept form of a line is y=mx+b.

Where m= slope and b= y-intercept.

First step is to compare the given equation y=35x+8 with the above equation to get the value of m.

After comparing the two equations we will get m=35.

Slope of paralle lines always equal which means slope of a line which is parallel to the above line will also be 35.

Now the line is passing through (-10,4).

Point slope form of a line is :

y-y_{1} =m(x-x_{1} )

Next step is to plug in m=35, x1=-10 and y1=4 in the above equation. So,

y-4=35(x-(-10)

y-4=35(x+10)

y-4=35x+350

y=35x+350+4

y=35x+354.

So, the equation of the line is y=35x+354.

4 0
4 years ago
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