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Simora [160]
4 years ago
13

On a spelling test of 25 words, patrick spelled 17 more words correctly than he spelled incorrectly. What percent of the words d

id he spell incorrectly?
Mathematics
2 answers:
Simora [160]4 years ago
5 0

Answer:

68 correct 32 incorrect

Step-by-step explanation:

Tpy6a [65]4 years ago
4 0
He got 68 percent of the words correct and 32 percent incorrect
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3t - 6 = 18 t = _____
Mazyrski [523]

Answer:

3t = 18 + 6 \\ 3t = 24 \\ 24 \div 3 = 8 \\ t = 8

Step-by-step explanation:

First we move the constant to the right and change its sign

we add the numbers and divide it by 3

and you get 8

3 0
3 years ago
A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five
exis [7]

Answer:

\dfrac{14}{29}

Step-by-step explanation:

Let <em>P(A) </em>be the probability that goggle of type A is manufactured

<em>P(B) </em>be the probability that goggle of type B is manufactured

<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

<em>P(A)</em> = 30%

<em>P(B)</em> = 70%

<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

P(A \cap E) will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

P(B \cap E) will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

P(E \cap A) = P(A) \times P(E/A)

P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%

P(E \cap B) = P(B) \times P(E/B)

P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%

P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

P(B/E) = \dfrac{P(E \cap B)}{P(E)}

\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}

So, the required probability is \dfrac{14}{29}.

7 0
4 years ago
If the AREA of the rectangle at the right is 22 3/4 square inches, what is the width of the rectangle?
sergejj [24]

Answer:

3.25 or 3 1/4 inches

Step-by-step explanation:

A = lw

22.75 = 7w

w = 3.25 which is 3 1/4

6 0
3 years ago
Suppose f(x) = 6x^2 + 2x − 7 and g(x) = 4x − 3. Find each of the following functions.
FinnZ [79.3K]

Step-by-step explanation:

(f+g)(x) ➡ f(x) + g(x) ➡ 6x^2 + 2x -7 + 4x - 3 =6x^2 + 6x - 10

(f-g)(x) ➡ f(x) - g(x) ➡ 6x^2 + 2x - 7 -4x + 3 = 6x^2 -2x -4

8 0
3 years ago
A new lawn has a perimeter of 278ft. And a width of 64ft. A bag of grass seed will cover 384ft of ground. How many bags of grass
Anit [1.1K]

Answer:

13 bags

Step-by-step explanation:

Area of the lawn: A=lw

w= 64 ft

P= 2(l+w)= 278 ft ⇒

  • l= 278/2- 64= 75 ft
  • A= 64*75= 4800 ft²

bags of seed required:

  • 4800/384= 12.5 so 13  full bags needed
7 0
3 years ago
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