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4 years ago

13

On a spelling test of 25 words, patrick spelled 17 more words correctly than he spelled incorrectly. What percent of the words d

id he spell incorrectly?

2 answers:

Simora [160]4 years ago

5 0

Answer:

68 correct 32 incorrect

Step-by-step explanation:

Tpy6a [65]4 years ago

4 0

He got 68 percent of the words correct and 32 percent incorrect

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T=months so if you have 7 months you would plug 7 in for (t)
making the equation g(7) = 2(7)

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3 years ago

HELP ME PLEASE⚠️ the question is in the picture

Pavlova-9 [17]

Answer:

Answer is 3

Step-by-step explanation:

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3 years ago

F(x)=x^4+3, g(x)=x-7 and h(x)=square root of x then f(g(h(x))=

SpyIntel [72]

Answer:

<em>x² - 28x√x + 294x - 1372√x + 2404 </em>

Step-by-step explanation:

f(x) = $x^{4}$ + 3

g(x) = x - 7

h(x) = √x

f(g(h(x))) - ?

g(h(x)) = √x - 7

f(g(h(x))) = $(\sqrt{x} -7) ^{4}$ + 3 = ( √x - 7 )² × ( √x - 7 )² + 3 =

= (x - 14√x + 49)(x - 14√x + 49) + 3 =

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3 years ago

Simplify 7(x - 1) - 2(x + 1) + 3(x - 4)<br><br> 8x - 21<br> 8x - 4<br> 8x + 21

Anna007 [38]

Answer:

all work is shown and pictured

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3 years ago

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago