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mariarad [96]
3 years ago
12

}^{2} = {16}^{x?} " alt=" {x }^{2} = {16}^{x?} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
lora16 [44]3 years ago
5 0
X is -1/2 . Using the Lambert W function.
x^2=16^x => x^2=(2^4)^x
x^2=2^4x => x=2^2x
x=(e^in(2))^2x => x=e^2in(2)x
e^2in(2)x1/x=1
xe^-2in(2)x=1 /*1
-xe^-2in(2)x=-1
-2in(2)xe^-2in(2)x=-2in(2)
W(-2in(2)xe^-2in2x)=W(-2in(2))
-2in(2)x=W(-2in(2))
X=-W(-2in(2))/2in(2)
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Given that cos(theta) = 8/17 and that theta lies in Quadrant IV, what is the exact value of sin 2(theta)?
Deffense [45]

Answer:    -\frac{240}{289}

=========================================================

Explanation:

Use the pythagorean trig identity \sin^2(\theta)+\cos^2(\theta) = 1 and plug in the fact that \cos(\theta) = \frac{8}{17}\\\\

Isolating sine leads to \sin(\theta) = -\frac{15}{17}\\\\. I'm skipping the steps here, but let me know if you need to see them.

The result is negative because we're in quadrant 4, when y < 0 so it's when sine is negative.

Therefore,

\sin(2\theta) = 2\sin(\theta)\cos(\theta)\\\\\sin(2\theta) = 2*\left(-\frac{15}{17}\right)*\left(\frac{8}{17}\right)\\\\\sin(2\theta) = -\frac{240}{289}\\\\

6 0
1 year ago
Which qoutients are equivalent to -2/3?
Mice21 [21]
The answers are : A and C
3 0
2 years ago
HELP DUE IN 10 MINS!
Scilla [17]

Answer:

\checkmark \text{B. The area of the circle is } 729\pi,\\\checkmark \text{D. The arc length of the sector is } 12\pi

Step-by-step explanation:

Area of a circle with radius r: r^2\pi

Circumference of a sector with radius r: 2r\pi

Area of sector with angle \theta:  r^2\pi\cdot \frac{\theta}{360}.

Arc length of sector with angle \theta: 2r\pi\cdot \frac{\theta}{360}

Using these equations, we get the following information:

Area of circle: 27^2\pi=729\pi

Circumference of a circle: 2\cdot 27\cdot \pi=54\pi

Area of sector: 27^2\pi\cdot \frac{80}{360}=162\pi

Arc length of sector: 2\cdot 27\cdot \pi \cdot \frac{80}{360}=12\pi

3 0
2 years ago
The curve with equation y2 = x3 + 3x2 is called the tschirnhausen cubic. find an equation of the tangent line to this curve at t
MAVERICK [17]
First find the slope, take derivative of both sides with respect to x.  
2y dy/dx=3x^2+6x
solve for dy/dx
dy/dx=[3x^2+6x]/2y
plug in given vales of (1,2(
dy/dx=9/4

now you have everything you need to plug into point slope form
y-2=(9/4)(x-1)
answer is y=(9/4)x+(1/4)
5 0
3 years ago
I need help on this ! Asap
Gnoma [55]

Answer:

1. Given

2, Exterior sides on opposite rays

3. Definition of supplementary angles

4. If lines are ||, corresponding angles are equal

5. Substitution

Step-by-step explanation:

For the first one, it is given as shown in the problem. Also in the figure you can see that line s is parallel to line t.

2. ∠5 and ∠7 are adjacent, they share a common side. Their non-common side are rays that go in a direction opposite of each other. Also you can see that they form a straight line, which means that they are supplementary.

3. Supplementary angles simply put are angles that sum up to 180°. You know this for sure because of proof 2, specifically the part that they form a straight line. The measure of a straight line is 180°.

4. Corresponding angles are congruent. These are angles that have the same relative position when a line is intersected by parallel lines. You have other example in the figure like ∠2 and ∠6; ∠3 and ∠7.

5. This is substitution because ∠1 substituted ∠5 in this case. Since ∠1 is equal to ∠5, then it can substitute it in the equation given in step 3. This means that ∠1 and ∠7 are supplementary as well.

8 0
3 years ago
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