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Aleonysh [2.5K]
3 years ago
10

What does it mean for a ordered pair to be a solution to a linear equation​

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

What's a Solution to a System of Linear Equations? Note: If you have a system of equations that contains two equations with the same two unknown variables, then the solution to that system is the ordered pair that makes both equations true at the same time.

Step-by-step explanation:

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2.5 ( y + ⅖ ) = -13<br> im really bad at math someone pls help
My name is Ann [436]

Answer:

-5.6

Step-by-step explanation:

first distribute the 2.5

also convert the 2/5 to decimal (0.4) because it's hard to work with both decimal and fraction

2.5y + 2.5*0.4 = -13

2.5y +1 = -13

y = -14/2.5 = -5.6

5 0
3 years ago
Write the decimal in simplest fractional form: 3.05
Sidana [21]
61/20 is the answer.
5 0
3 years ago
Read 2 more answers
6Of
marysya [2.9K]

Answer:

I believe the answer is the system has one solution. Both lines have the same y-intercept. And the solution is the intersection of the 2 lines.

4 0
3 years ago
Simplify the expression. 12^–3 • 12^10 • 12^0
butalik [34]
Since they have the same base we can just add all the exponents

-3+ 10= 7

keep the base so the answer is
12^7
7 0
3 years ago
The equation of a parabola is y=x^2-10x+27. Write the equation in vertex form
azamat

Answer:

\large \boxed{y = (x - 5)^{2} + 2 }

Step-by-step explanation:

y = x² - 10x + 27

y = ax² + bx + c

This is the general form of the equation for a parabola.

We must convert it to the vertex form

y = (x - h)² + k, where (h,k) are the coordinates of the vertex.

We can do this by completing the square.

\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}The figure below shows that your parabola has its vertex at (5,2).

4 0
3 years ago
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