A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms
Balls height 
To find all values of t for which the ball's height is 3 meters
We plug in 3 for h and solve for t
Solve for t
Solve using quadratic formula
After simplifying this,
= 0.11898
= 1.68102
the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec
Answer:
multiply
Step-by-step explanation:
and then you are going to break it down
Answer:
33
Step-by-step explanation:
So the angle of 40 is a vertical angle with the one opposite of it, meaning that the triangle on the left would have two values of 40 and 41, to find the value of the 3rd angle of the left triangle, you can subtract 40 and 41 from 180 which is the total number of degrees in a triangle to get 99, then you can find the degrees of the triangle on the right's bottom angle by subtracting 99 from 180, meaning the bottom left angle would be 81, then you can do the same to find the other angle by subtracting 114 from 180 to get 66. Lastly you can add 81 and 66 to get 147, then subtracting 147 from 180 you would get x=33
Answer:
i tried it by trial and error, and my work is below.
Step-by-step explanation:
2x + 9 = 23
subtract 9 from both sides
2x = 14
guess.... lol
x=7
