Hello!
We have two probabilities we can use; we have 170/400, for our experiment, and 1/2, which is our theoretical probability.
To solve, we just multiply the two probabilities.
=0.2125≈21.3
Therefore, we have about a 21.3% chance of this event occurring.
I hope this helps!
Answer:
The probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
Step-by-step explanation:
Let <em>X</em> = number of household owns a sports car.
The probability of <em>X</em> is, P (X) = p = 0.07.
Then the random variable <em>X</em> follows a Binomial distribution with <em>n</em> = 3 and <em>p</em> = 0.07.
The probability function of a binomial distribution is:
![P(X=x) = {n\choose x}p^{x}[1-p]^{n-x}\\](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20%7Bn%5Cchoose%20x%7Dp%5E%7Bx%7D%5B1-p%5D%5E%7Bn-x%7D%5C%5C)
Compute the probability that of the 3 households randomly selected at least 1 owns a sports car:

Thus, the probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
Answer:
15.
Step-by-step explanation:
The new average will be 11 + 4 = 15.
Factor out like terms
-y(7+y)=0
Area=length * width
You know area and width. Plug in and solve.
24=length*4
Length =6 meters