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lisov135 [29]
4 years ago
13

Eunice and Belinda weighs 267 pound 6 ounces. Eunice and Laura weighs 223 pounds and 8 ounces. Laura weighs 136 pounds and 11 ou

nces. How much does Belinda weigh?
Mathematics
1 answer:
Ad libitum [116K]4 years ago
5 0

Answer:

180  9/16 lb

Step-by-step explanation:

Let the weights of the three girls be E, B and L.

Note that E + L = 223  8/16 lb, so subtracting L from both sides, that is, subtracting 136  11/16 lb from both sides, results in:

                E = 223  8/16 lb  -  136  11/16 lb  =  86  13/16 lb

Thus, E's weight is 86  13/16 lb,

          B's weight is 267  6/16 lb  -  86  13/16 lb = 180  9/16 lb

          L's weight is 136 11/16 lb.

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In an anthropology class there are 77 anthropology majors and 1414 non-anthropology majors. 55 students are randomly selected to
Nata [24]

Answer:

P = 0.9989

Step-by-step explanation:

In order to do this, I will use the following numbers to make the calculations easier. In this case, We'll say that we have 7 majors and 14 non majors anthopology to present a topic.

This means that in the class we have 21 students.

Now, we choose 5 of them, and we want to know the probability that 1 of them is non major.

First, we need to calculate the number of ways we can select the students in all cases, and then, the probability.

First, we'll use the combination formula, to calculate the number of ways we can select the 5 students out of the 21. We use combination, because it does not matter the order that the students are selected.

C = m! / n!(m - n)!

Where:

m: number of students

n: number of selected students out of m.

With this expression we will calculate first, how many ways we can choose the 5 students out of 21:

C1 = 21! / 5!(21-5)! = 20,349

Now let's calculate the number of ways you can get the all 5 students are non majors:

C2 = 14! / 5!(14 - 5)! = 2002

Now we need to know the number of ways we can get 4 non majors and 1 major:

C3 = C3' * C3''

C3' represents the number of ways we can get 4 non majors and the C3'' represents the number of ways we can get 1 major.

C3' = 14! / 4!(14 - 4)! = 1,001

C3'' = 7! / 1!(7 - 1)! = 7

C3 = 1001 * 7 = 7,007 ways to get 4 non majors and 1 major

Now the way to get 3 non majors and 2 majors, we do the same thing we do to get 4 non majors and 1 major, but changing the numbers. Then the way to get 2 non majors and 3 majors, and finally 1 non major and 4 majors:

3 non majors and 2 majors:

C4 = C4' * C4'' = [14! / 3!(14 - 3)!] * [7! / 2!(7 - 2)!] = 7,644

2 non majors and 3 majors:

C5 = C5' * C5'' = [14! / 2!(14 - 2)!] * [7! / 3!(7 - 3)!] = 3,185

1 non major and 4 majors:

C6 = C6' * C6'' = [14! / 1!(14 - 1)!] * [7! / 4!(7 - 4)!] = 490

Finally to know the probability of getting 1 out of the 5 to be non major, we have to sum all the previous results, and divide them by the ways we can choose the 5 students (C1):

P = 2,002 + 7,007 + 7,644 + 3,185 + 490 / 20,349

P = 0.9989

5 0
4 years ago
Find the volume of the solid. Round your answer to the nearest tenth
insens350 [35]

Answer:

Solution given:

Volume of cone=⅓πr²h

Volume of cylinder=πr²h

1.

volume =πr²h=π*(10/2)²*6=<u>471.23mm³</u>

2.

Volume =πr²h=π*8*12.5=<u>314.16in³</u>

3.

volume =⅓πr²h=⅓*π*4²*3=<u>5</u><u>0</u><u>.</u><u>2</u><u>6</u><u>c</u><u>m</u><u>³</u>

4.

Volume =⅓πr²h=⅓*π*(8/2)²*12=<u>2</u><u>0</u><u>1</u><u>.</u><u>0</u><u>6</u><u>i</u><u>n</u><u>³</u>

5 0
3 years ago
Please help ASAP please and thank you have a great and blessed day!
goldenfox [79]
<
>
=
>
is going to be your answers i believe
3 0
3 years ago
Read 2 more answers
Find the 7th term of the sequence
NikAS [45]

Answer:

3rd option, 4096

Step-by-step explanation:

4⁰ = 1, 1st term

4¹ = 4, 2nd term

4² = 16, 3rd term

.

.

.

4⁶ = 4096, 7th term

Answered by GAUTHMATH

8 0
3 years ago
Which of these values for the number of yards in a mile is most accurate, when compared to the exact value?
Bogdan [553]
It would be D-1,755 because there are 1,760 yards in a mile exactly. Have a good day!
5 0
3 years ago
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