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3 years ago

Write an equation for a line parallel to y = 0.25x − 5 that passes through the point (8, 5).

Mathematics

1 answer:

Usimov [2.4K]3 years ago

6 0

Answer:

y= 0.25x +3

Step-by-step explanation:

Slope-intercept form

y= mx +c, where m is the slope and c is the y-intercept.

y= 0.25x -5

This equation is already in the slope-intercept form, hence we can easily identify its slope from the coefficient of x.

Slope= 0.25

Parallel lines have the same slope.

Thus, the slope of the line is also 0.25.

Substitute m= 0.25:

y= 0.25x +c

To find the value of c, substitute a pair of coordinates.

When x= 8, y= 5,

5= 0.25(8) +c

5= 2 +c

c= 5 -2

c= 3

Hence, the equation of the line is y= 0.25x +3.

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navik [9.2K]

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You gave the explicit form.

Step-by-step explanation:

You gave the explicit form.

The recursive form is giving you a term in terms of previous terms of the sequence.

So the recursive form of a geometric sequence is $a_n=r \cdot a_{n-1}$ and they also give a term of the sequence; like first term is such and such number. All this says is to get a term in the sequence you just multiply previous term by the common ratio.

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-54/18

18/-6

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If these quotients didn't match, then it wouldn't be geometric.

Anyways the recursive form for this geometric sequence is

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