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I am Lyosha [343]
2 years ago
14

*15 points help easy question*

Mathematics
1 answer:
DIA [1.3K]2 years ago
8 0

Answer:

x = 12

Step-by-step explanation:

The segment from the vertex to the base is a perpendicular bisector.

Using Pythagoras' identity on the right triangle on the right.

(\frac{1}{2} x )² + 3² = (\sqrt{45} )² , that is

\frac{1}{4} x² + 9 = 45 ( subtract 9 from both sides )

\frac{1}{4} x² = 36 ( multiply both sides by 4 )

x² = 144 ( take the square root of both sides )

x = \sqrt{144} = 12

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We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

</span>we have that
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</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2 
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3

radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
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A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>


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