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3 years ago

⦁ Find the distance between the two numbers

Mathematics

2 answers:

Temka [501]3 years ago

8 0

1. 12+19=31
2. -14
3.0

Troyanec [42]3 years ago

8 0

there answer is incorrect

-12, 19 is 7

-2, -7 is 5

25, -1 is 24

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5-2x=15 <img src="https://tex.z-dn.net/?f=5%20-%202x%20%3D%2015" id="TexFormula1" title="5 - 2x = 15" alt="5 - 2x = 15" align

padilas [110]

5-2x=15

 $5-2x=15 \\ \\ -2x= 15-5 \\ \\ -2x= 10 \\ \\ x= \dfrac{10}{-2} \to \boxed{x= -5}$

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4 years ago

What is the product of the polynomials below? (3x^2 - 2x - 3)(5x^2 + 4x + 5)

frozen [14]

Answer:

15x^4+2x^3-8x^2-22x-15

Step-by-step explanation:

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4 years ago

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A recipe for quinoa calls 2 2/3 cups of milk. Conner wants to makes 4 batches of quinoa. How much milk does he needs

krek1111 [17]

10 2/3 cups of milk for 4 batches

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4 years ago

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The water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters). If

Alecsey [184]

Answer:

The resultant velocity is 12.21 m/s.

Step-by-step explanation:

We are given that the water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters).

Also, v Subscript x is constant at 10.0 m/s.

The water from a fire hose follows a path described by the following equation below;

$y=2.0 + 0.9x-0.10x^{2}$

The velocity of the $x$ component is constant at = $v_x=10.0 \text{ m/s}$

and the point at which resultant velocity has to be calculated is (9.0,2.0).

Let the velocity of x and y component be represented as;

$v_x=\frac{dx}{dt} \text{ and } v_y=\frac{dy}{dt}$

Now, differentiating the above equation with respect to t, we get;

$y=2.0 + 0.9x-0.10x^{2}$

$\frac{dy}{dt} =0 + 0.9\frac{dx}{dt} -(0.10\times 2)\frac{dx}{dt}$

$\frac{dy}{dt} = 0.9\frac{dx}{dt} -0.2\frac{dx}{dt}$

$v_y = 0.9v_x -0.2v_x$

$v_y = 0.7v_x$

Now, putting $v_x=10.0 \text{ m/s}$ in the above equation;

$v_y = 0.7 \times 10.0$ = 7 m/s

Now, the resultant velocity is given by = $v=\sqrt{v_x^{2}+v_y^{2} }$

$v=\sqrt{10^{2}+7^{2} }$

= $\sqrt{149}$ = 12.21 m/s

5 0

3 years ago

A family has two cars. During one particular week, the first car consumed 15 gallons of gas. The two cars Drove a combined total

julia-pushkina [17]

Answer:

Car 1 : 40 miles per gallon

Car 2: 25 miles per gallon

Step-by-step explanation:

family has two cars. During one particular week, the first car consumed 15 gallons of gas. The second car consumed 25 gallons of gas. The two cars Drove a combined total of 1475 miles and the sum of their fuel efficiency was 65 miles per gallon. What were the fuel efficiency of each of the cars that week

Given that :

Fuel efficiency , car 1 = x

Fuel efficiency , car 2 = y

x + y = 65 - - (1)

15x + 35y = 1475 - - - (2)

x = 65 - y

15(65-y) + 35y

975 - 15y + 35y = 1475

20y = 14875 - 975

20y = 500

y = 25

Put y = 25 in (1)

x + y = 65

x + 25 = 65

x = 65 - 25

x = 40

6 0

3 years ago