Can one line be shorter than the other and still be parallel

I need the answer for 90 please its due tommorow!

babunello [35]

Jacqueline is incorrect.
To find how much trash you can clean in 4 days if you already know how much trash you can clean in one day, multiply 1 2/3 (how much you can clean in one day) by 4.
Another way to write 1 and 2/3 miles is 5/3 (converting a mixed number to a single fraction). Then, 5/3 x 4 = 20/3. (To multiply fractions, just multiply across, leaving 5 x 4 in the numerator and 4 x 1 in the denominator.)
Jacqueline said you would be able to clean 19/3 miles but you can actually clean 20/3.

4 0

3 years ago

Read 2 more answers

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

4 0

3 years ago

Solve the inequality and express your answer in interval notation<br> x^2+8x+5 <0

irakobra [83]

The interval notation is $(-\sqrt{11}-4, \sqrt{11}-4)$

Explanation:

The inequality is $x^{2}+8 x+5$

Let us complete the square, we get,

$x^{2}+8 x+5+4^{2}-4^{2}$

Simplifying, we have,

$(x+4)^{2}+5-4^{2}$

$(x+4)^{2}-11$

Adding both sides of the equation by 11, we get,

$(x+4)^{2}$

Since, we know that for $u^{n}$ , if n is even then $-\sqrt[n]{a}$

Thus, writing the above expression in this form, we get,

$-\sqrt{11}$

Also, if $a$ then $a$ and $u$

Then ,we have,

$-\sqrt{11}$ and $x+4$

Solving the inequalities, we get,

$-\sqrt{11}\ \ \ \ \ \$ and $x+4$

Merging the intervals, we have,

$-\sqrt{11}-4$

Hence, writing the solution in interval notation, we have,

$(-\sqrt{11}-4, \sqrt{11}-4)$

Therefore, the answer is $(-\sqrt{11}-4, \sqrt{11}-4)$

7 0

3 years ago

The average college lecture hall (auditorium) can seat 60 students with a standard deviation of 21. Assume that a total of 60 le

fiasKO [112]

Answer:

The standard deviation of the sample mean is $\sigma _ {\= x } = 2.711$

Step-by-step explanation:

From the question we are told that

The mean is $\= x = 60$

The standard deviation is $\sigma = 21$

The sample size is $n = 60$

Generally the standard deviation of the sample mean is mathematically represented as

$\sigma _ {\= x } = \frac{\sigma }{\sqrt{n} }$

substituting values

$\sigma _ {\= x } = \frac{ 21 }{\sqrt{60} }$

$\sigma _ {\= x } = 2.711$

4 0

3 years ago

A spotlight is made by placing a strong light bulb inside a reflective paraboloid formed by rotating the parabola x^2=4y around

Nadya [2.5K]

Answer:

1.00 inches

Step-by-step explanation:

The distance from vertex to focus is "p" in the quadratic equation ...

x^2 = 4py

In the given equation, p=1. Since units are inches, ...

the bulb should be placed 1.00 inches from the vertex.

7 0

3 years ago