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4 years ago

Help me with all of 9

Mathematics

2 answers:

TEA [102]4 years ago

6 0

A. 4/9
b. 3/4
c. 9/3
d. 2/9
e. 1/1
I hope that helped you. :)

Alex17521 [72]4 years ago

6 0

Let me help you what does the question say

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Round 3.5 to the nearest whole number

sweet [91]

4 (5 and up round up --- 4 and below round down)

6 0

3 years ago

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What is the length of the diameter of a circle if the endpoints of the diameter are at the points (4, 2) and (–6, –1)?

Oksana_A [137]

Answer:

d= 10.44030651

Step-by-step explanation:

The diameter is the length between the endpoints. We can find it using the distance formula.

d= sqrt((x2-x1)^2+(y2-y1)^2 )

d = sqrt((-6-4)^2+ (-1-2)^2)

d = sqrt((-10)^2+(-3)^2)

d= sqrt(100+9)

d = sqrt(109)

d= 10.44030651

3 0

3 years ago

Help fast pls. Need it due fast

Gelneren [198K]

3x+8=5x-1
3x-5x=-1-8
-2x=-9
x=4,5

AM=3x4,5+8=21,5
MB=5x4,5-1=21,5
AB=AM+MB
AB=21,5+21,5=43

6 0

3 years ago

Read 2 more answers

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago

Write the equation in standard form<br><br> y = -10x + 6

Mumz [18]

Step (1) Flip the equation

−10x+6=y

Step (2) Add -6 to both sides

−10x+6+−6=y+−6

−10x=y−6

Step (3) Divide both sides by -10

−10x−10=y−6−10

ANSWER
$x = \frac{ - 1}{10} y + \frac{3}{5}$

5 0

3 years ago