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Lynna [10]
3 years ago
14

IF THE PRODUCT OF 2 FRACTIONS EQUAL 2/3 AND ONE FRACTION IS 3/5 WHAT IS THE OTHER FRACTION?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0
So product means multiplication
so

x times y =2/3

one is 3/5 so
x times 3/5=2/3
x times 3/5=x(3/5)=2/3
x(3/5)=2/3
multiply both sdies by 5/3 to clear fraction
x(15/15)=(2/3)(5/3)
x(1)=(2 times 5)/(3 times 3)
x=10/9
the other number is 10/9 or 1  and 1/9
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The 4th and 8th term of a G.P. are 24 and 8/27 respectively. find the 1st term and common ratio
beks73 [17]

Answer:

see explanation

Step-by-step explanation:

The n th term of a geometric progression is

• a_{n} = a₁ r^{n-1}

where a₁ is the first term and r the common ratio

given a₄ = 24, then

a₁r^{3} = 24 → (1)

Given a₈ = \frac{8}{27}, then

a₁r^{7} = \frac{8}{27} → (2)

Divide (2) by (1)

r^{4} = \frac{\frac{8}{27} }{24} = \frac{1}{81}

Hence r = \sqrt[4]{\frac{1}{81} } = \frac{1}{3}

Substitute this value into (1)

a₁ × (\frac{1}{3} )³ = 24

a₁ × \frac{1}{27} = 24, hence

a₁ = 24 × 27 = 648

4 0
3 years ago
Help ASAP!!!<br><br> Identify the correct trigonometry formula to use to solve for x.
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Step-by-step explanation:

7 0
3 years ago
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6 0
3 years ago
-4rover4+5rover3 please help me
Alchen [17]

Solution, \frac{-4r}{4}+\frac{5r}{3}=\frac{2r}{3}

Steps:

\frac{-4r}{4}+\frac{5r}{3}

\frac{-4r}{4},\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b},\\-\frac{4r}{4},\\\mathrm{Divide\:the\:numbers:}\:\frac{4}{4}=1,\\-r,\\-r+\frac{5r}{3}

\mathrm{Convert\:element\:to\:fraction}:\quad \:r=\frac{r3}{3},\\\frac{5r}{3}-\frac{r\cdot \:3}{3}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c},\\\frac{5r-r\cdot \:3}{3}

5r-r\cdot \:3,\\\mathrm{Add\:similar\:elements:}\:5r-3r=2r,\\\frac{2r}{3}

The\:Correct\:Answer\:Is\:\frac{2r}{3}

Hope\:This\:Helps!!!

-Austint1414

5 0
3 years ago
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