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Lynna [10]
3 years ago
14

IF THE PRODUCT OF 2 FRACTIONS EQUAL 2/3 AND ONE FRACTION IS 3/5 WHAT IS THE OTHER FRACTION?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0
So product means multiplication
so

x times y =2/3

one is 3/5 so
x times 3/5=2/3
x times 3/5=x(3/5)=2/3
x(3/5)=2/3
multiply both sdies by 5/3 to clear fraction
x(15/15)=(2/3)(5/3)
x(1)=(2 times 5)/(3 times 3)
x=10/9
the other number is 10/9 or 1  and 1/9
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Andres works at a job that pays him 12.50 an hour.Andres works 30 hours a week.How much does he make each month after 30% of cal
BlackZzzverrR [31]

Answer:

he makes $112.50

Step-by-step explanation:

first you have to find out how much he makes before tax is taken out. all you do is multiply 12.50 by 30, which gives you $375.00. then, you can either put in the calculator 30%375 or 0.3×375(both are the same thing) and you should get $112.50

8 0
3 years ago
In the function y=5x^2-2, what effect does the number 5 have on the graph, as compared to the graph of y=x^2?
allochka39001 [22]

General Idea:

The Rules for Transformations of Functions are given below:

If f(x) is the original function, a > 0 and c > 0; Then

f(x)+k \; \; shift \; f(x) \; UPWARD \; k \; units\\\\f(x)-k \; \; shift \; f(x) \; DOWNWARD \; k \; units\\\\f(x+h) \; \; shift \; f(x) \; LEFT \; h \; units\\\\f(x-h) \; \; shift \; f(x) \; RIGHT \; h \; units\\\\-f(x) \; \; REFLECT \; f(x) \; in \; the \; x-axis\\\\f(-x) \; REFLECT \; f(x) \; in \; the \; y-axis\\\\a \cdot f(x), \; a>1 \; STRETCH \; f(x) \; vertically \; by \; a \; factor \; of \; a\\\\a \cdot f(x), \; 0

f(ax), \; a>1 \; SHRINK \; f(x) \; horizontally \; by \; a \; factor \; of \;\frac{1}{a}  .\\\\f(ax), \; 0

Applying the concept:

In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:

C.it stretches the graph vertically by a factor of 5

4 0
3 years ago
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rjkz [21]

Answer:

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Step-by-step explanation:

a

8 0
2 years ago
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What is the solution to this system of linear equations?<br><br> x + y = 4<br><br> x − y = 6
Amiraneli [1.4K]
X+y = 4, therefore y = 4-x when you rearrange the equation.
You can subsitute this in: x-(4-x) = 6
-4+x = 6-x
x=10-x
2x = 10
x = 5
Substitute x into the previous equation:
5+y = 4
y = 4-5
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5 0
3 years ago
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A spring exerts a force of 6 N when stretched 3 m beyond its natural length. How much work is required to stretch the spring 2 m
lys-0071 [83]

Answer:

4Joules

Step-by-step explanation:

According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

K is the elastic constant

e is the extension

If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'

can be gotten using k = f/e where

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K = 2N/m

Work done on an elastic string is calculated using 1/2ke².

If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;

1/2× 2× (2)²

= 4Joules

3 0
3 years ago
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