Question

A 3650​-year-old wooden chest is found by archaeologists. What percentage of the original Superscript 14 Baseline Upper C would you expect to find in the wooden​ chest? (Recall that the decay constant for Superscript 14 Baseline Upper C is​ 0.00012.)

Answer 1

Answer:

64.5%

Step-by-step explanation:

Initial amount N° = ?

Remaining amount after decay = N = ?

k = decay constant =  0.00012 $yr^{-1}$

t = time = 3650​ year

fraction remaining will be N/N°

From the decay equation, N = N°$e^{-kt}$

N/N° = $e^{-kt}$

N/N° = $e^{-0.00012 x 3650 }$

N/N° = $e^{-0.438}$

N/N° = 0.645 = 64.5%