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4 years ago

How would you classify sugar? 4)

1 answer:

4 0

If by sugar you're referring to glucose, then this is a pure substance-compound. Glucose isn't an element, as it's made of carbon, hydrogen, and oxygen. Because sugar is a molecule (and not a mixture), this leaves A as the only possible answer. Hope this helps!

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How many kg are in 50 lb luggage bag

Darya [45]

There are 0.454 kg in 1 lb

Cross multiply

0.454 kg = 1 lb
X kg. = 50 lb

50* 0.454 = 22.7 kg

Answer : 22.7 kg in 50 lbs

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4 years ago

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Name of Metallic compound VSe

Komok [63]

Answer: vanadium selenide

Explanation:

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3 years ago

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The size of an atom would be described in _______.

Andreas93 [3]

Answer:

atomic radius

Explanation:

so radius

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3 years ago

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For each given [H3O+] or [OH-], find the corresponding [OH-] or [H3O+] at 25°C.

-BARSIC- [3]

Answer:

a) [H3O+] = 1.00 E-10 M ⇒ [OH-] = 1.0 E-4 M

b) [H3O+] = 1.00 E-4 M ⇒ [OH-] = 1.0 E-10 M

c) [H3O+] = 9.90 E-6 M ⇒ [OH-] = 1.0 E-9 M

Explanation:

14 = pH + pOH
pH = - Log [H3O+]

a) [H3O+] = 1.00 E-10 M

⇒ pH = - Log(1.00 E-10) = 10

⇒ pOH = 14 - 10 = 4

⇒ 4 = - Log[OH-]

⇒ [OH-] = 1.0 E-4 M

b) [H3O+] = 1.00 E-4 M

⇒ pH = 4

⇒ pOH = 10

⇒ [OH-] = 1.0 E-10 M

c) [H3O+] = 9.90 E-6 M

⇒ pH = 5

⇒ pOH = 9

⇒ [OH-] = 1.0 E-9 M

8 0

3 years ago

How many grams are in 9.97 moles of Be(NO3)2?<br> Use two digits past the decimal for all values.

Simora [160]

Answer:

1,869.97 grams of Be(NO3)2

Explanation:

Be(NO3)2 = Be N2 O6

Be=9.012182g/mole

N2=28.0134g/mole

O6=96g/mole

therefore Be(NO3)2 gives you 187.56g in one mole

so 9.97 moles means there is 9.97 times more

9.97mole Be(NO3)2 * 187.56g Be(NO3)2/1mole Be(NO3)2 = 1,869.97g of Be(NO3)2

4 0

3 years ago